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Mademuasel [1]
3 years ago
6

YO CAN ANYONE DO THE BLANK COLUMN AND THE QUESTION PART RQ PLS!!

Physics
1 answer:
VikaD [51]3 years ago
6 0

Answer:

stryo:  1

wood: 1

ice: 1

brick: 2

aluminum: 2.7

Explanation:

d= mass/ total volume

(fyi: for aluminum, they did the subtraction wrong to find the total volume. it is actually 5 or 5.00)

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A fisherman has caught a very large, 5.0 kg fish from a dock that is 2.0 m above the water. He is using lightweight fishing line
sergeinik [125]

Answer:

The least amount of time in which the fisherman can raise the fish to the  dock without losing it is t= 2 seconds.

Explanation:

m= 5 kg

h= 2m

Fmax= 54 N

g= 9.8 m/s²

W= m * g

W= 49 N

F= Fmax - W

F= 5 N

F=m*a

a= F/m

a= 1 m/s²

h= a * t²/2

t= √(2*h/a)

t= 2 seconds

6 0
3 years ago
A table with mass 23.5 kg sits on the ground what is the normal force on the table?
marin [14]

Answer:

C

Explanation:

There are two forces on the table: weight and normal force.  Newton's second law:

∑F = ma

N - mg = 0

N = mg

N = (23.5 kg) (9.81 m/s²)

N = 230 N

6 0
3 years ago
Read 2 more answers
NEED HELP PLEASE!!!
kenny6666 [7]

Answer:

The gravitational potential energy the barbells have at the maximum height, is P.E. = 3680·h J = 1.10 × 10⁴ units

Where;

h = The maximum height to which he lifts the barbells

Explanation:

The given parameters are;

The  amount of work done by the championship lifter in lifting the weight, W = 1.10 × 10⁴ units

The weight of the barbells lifted by the championship lifter, N = 3680 N

The gravitational potential energy, P.E., the barbells had at their maximum height of lift is given as follows;

P.E. = m × g × h

Where;

m = The mass of the barbells;

g = The acceleration due to gravity = 9.8 m/s²

h = The maximum height to which the barbells are lifted by the championship weight lifter

m × g = The weight of the barbells = 3680 N

∴ P.E. = 3680 N × h = 3680·h J

By the conservation of energy principle, work done by the championship weight lifter = The maximum gravitational potential energy gained by the barbell = The gravitational potential energy at the maximum height, P.E.

∴ The gravitational potential energy the barbells have at the maximum height, P.E. = 3680·h J = W = 1.10 × 10⁴ units

3 0
3 years ago
Will give brainliest to correct answer.
Darina [25.2K]

Answer:

1.5X10^-4C

Explanation:

Expression for the electric force between the two charges is given by -

F = (k*q1*q2) / r^2

Here, k = constant = 9 x 10^9 N*m^2 / C^2

q1 = unknown

F=25N

q2 = 1.9x10^-6 C

r = 0.32 m

Substitute the given values in the above expression -

25=9x10^9 *(q1) * 1.9 x10^ -6/ (0.32m)^2

25= 17,100* (q1)/ 0.1024

multiply both sides by 0.1024 to get rid of the denominator

2.56=17,100*(q1)

Divide both sides by 17,100 to isolate q1

q1=1.5x10^-4C

4 0
3 years ago
A bowling ball has a mass of 6 kg. What happens to its momentum when its speed increases from 2 m/s to 4 m/s?
Ket [755]
The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s
4 0
3 years ago
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