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Mademuasel [1]
3 years ago
6

YO CAN ANYONE DO THE BLANK COLUMN AND THE QUESTION PART RQ PLS!!

Physics
1 answer:
VikaD [51]3 years ago
6 0

Answer:

stryo:  1

wood: 1

ice: 1

brick: 2

aluminum: 2.7

Explanation:

d= mass/ total volume

(fyi: for aluminum, they did the subtraction wrong to find the total volume. it is actually 5 or 5.00)

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A simple harmonic oscillator has an amplitude of 3. 50 cm and a maximum speed of 26. 0 cm/s. What is its speed when the displace
Marianna [84]

Answer:

1.) A simple harmonic oscillator has an amplitude of 3.50 cm and a maximum speed of 26.0 cm/s. What is its speed when the displacement is 1.75 cm? 2.) Both pendulum A and B are 3.0 m long. The period of A is T. Pendulum A is twice as heavy as pendulum B. What is the period of B? 3.) The time for one cycle of a periodic process is called the _ ? 4.) In simple harmonic motion, the acceleration is proportional to? 5.) The position of a mass that is oscillating on a spring is given by x= (18.3 cm) cos [(2.35 s-1)t]. What is the frequency of this motion?

Explanation:

3 0
1 year ago
Juan rides his horse with a constant<br> speed of 18 km/h. How far can he travel<br> in 1/2 hour?
Brut [27]

Answer:

He traveled 9km

Explanation:

To do this problem you need to use the equation which is Speed= distance/time and this problem gives you the speed which is 18 km/h and it gives you the time 1/2 hour so you write the equation 18= d/ 1/2 which his distance is 9km

3 0
3 years ago
Without using a micrometer screw gauge, how do I find the average diameter of a long piece of thin wire using a metre rule and a
Mice21 [21]

Answer:

Wind the long piece of thin wire around the uniform glass rod multiple times, find the length of the total diameters using the metre ruler, and divide by the number of times you wound it around the rod.

Explanation:

Since the diameter of one long piece of thin wire is too thin to be measured by a metre ruler, you can wind it multiple times and push it side by side to get a length you can measure.

For example, if you wound it around 20 times and the total length of 20 diameters of the wire side-by-side is 2.0 cm, one winding, which is the diameter would be 2.0cm ÷ 20 = 0.10cm or 1mm.

5 0
2 years ago
The electron cloud model describes which of the following?
GalinKa [24]
1. I think it's the trails left by an electron as it moves around the nucleus.

2. The atomic number is the number of protons so it is 8.

3. It's mass is lowered but it is still the same element.
3 0
3 years ago
Read 2 more answers
A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of
Gennadij [26K]

To solve this problem we will apply the concepts related to the electric field such as the smelting of the Force and the load (In this case the force is equivalent to the weight). Later we will apply the ratio of the total charge as a function of the multiplication of the number of electrons and their individual charge.

E = \frac{mg}{q}

Here,

m = mass

g = Acceleration due to gravity

Rearranging to find the charge,

q = \frac{mg}{E}

Replacing,

q = \frac{(3.37*10^{-9})(9.8)}{11000}

q = 3.002*10^{-12}C

Since the field is acting upwards the charge on the drop should be negative to balance it in air. The equation to find the number of electrons then is

q = ne

Here,

n = Number of electrons

e = Charge of each electron

n = \frac{q}{e}

Replacing,

n = \frac{3.002*10^{-12}}{1.6*10^{-19}}

n = 2.44*10^7

Therefore the number of electrons that reside on the drop is 2.44*10^7

5 0
3 years ago
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