Answer:
The least amount of time in which the fisherman can raise the fish to the dock without losing it is t= 2 seconds.
Explanation:
m= 5 kg
h= 2m
Fmax= 54 N
g= 9.8 m/s²
W= m * g
W= 49 N
F= Fmax - W
F= 5 N
F=m*a
a= F/m
a= 1 m/s²
h= a * t²/2
t= √(2*h/a)
t= 2 seconds
Answer:
C
Explanation:
There are two forces on the table: weight and normal force. Newton's second law:
∑F = ma
N - mg = 0
N = mg
N = (23.5 kg) (9.81 m/s²)
N = 230 N
Answer:
The gravitational potential energy the barbells have at the maximum height, is P.E. = 3680·h J = 1.10 × 10⁴ units
Where;
h = The maximum height to which he lifts the barbells
Explanation:
The given parameters are;
The amount of work done by the championship lifter in lifting the weight, W = 1.10 × 10⁴ units
The weight of the barbells lifted by the championship lifter, N = 3680 N
The gravitational potential energy, P.E., the barbells had at their maximum height of lift is given as follows;
P.E. = m × g × h
Where;
m = The mass of the barbells;
g = The acceleration due to gravity = 9.8 m/s²
h = The maximum height to which the barbells are lifted by the championship weight lifter
m × g = The weight of the barbells = 3680 N
∴ P.E. = 3680 N × h = 3680·h J
By the conservation of energy principle, work done by the championship weight lifter = The maximum gravitational potential energy gained by the barbell = The gravitational potential energy at the maximum height, P.E.
∴ The gravitational potential energy the barbells have at the maximum height, P.E. = 3680·h J = W = 1.10 × 10⁴ units
Answer:
1.5X10^-4C
Explanation:
Expression for the electric force between the two charges is given by -
F = (k*q1*q2) / r^2
Here, k = constant = 9 x 10^9 N*m^2 / C^2
q1 = unknown
F=25N
q2 = 1.9x10^-6 C
r = 0.32 m
Substitute the given values in the above expression -
25=9x10^9 *(q1) * 1.9 x10^ -6/ (0.32m)^2
25= 17,100* (q1)/ 0.1024
multiply both sides by 0.1024 to get rid of the denominator
2.56=17,100*(q1)
Divide both sides by 17,100 to isolate q1
q1=1.5x10^-4C
The initial momentum is 12 kg*m/s, and the final momentum is 24 kg*m/s