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Mademuasel [1]
3 years ago
6

YO CAN ANYONE DO THE BLANK COLUMN AND THE QUESTION PART RQ PLS!!

Physics
1 answer:
VikaD [51]3 years ago
6 0

Answer:

stryo:  1

wood: 1

ice: 1

brick: 2

aluminum: 2.7

Explanation:

d= mass/ total volume

(fyi: for aluminum, they did the subtraction wrong to find the total volume. it is actually 5 or 5.00)

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The luxury liner Queen Elizabeth 2 has a diesel-electric powerplant with a maximum power of 90 MW at a cruising speed of 31.5 kn
AlexFokin [52]

Answer:

5558643.69 N

Explanation:

F = Force

v = Velocity = 31.5 knots

Converting to m/s

1\ knot=0.514\ m/s

31.5\ knot=31.5\times 0.514\ m/s=16.191\ m/s

Power is given by

P=Fv\\\Rightarrow F=\frac{P}{v}\\\Rightarrow F=\frac{90\times 10^6}{16.191}\\\Rightarrow F=5558643.69\ N

The forward force is exerted on the ship at this highest attainable speed is 5558643.69 N

5 0
3 years ago
PLEASE HELP NOT A LOT OF TIME LEFT!!!!!
GenaCL600 [577]
D. 65.1 is the answer
8 0
3 years ago
A physicist makes a cup of instant coffee and notices that, as the coffee cools, its level drops 3.00 mm in the glass cup. Show
Lady bird [3.3K]

Answer:

change in height  is 1.664 mm

Explanation:

Given data

drops = 3.00 mm

diameter = 5.00 cm = 0.05 mm

decrease  =  350 cm^3

temperature = 95°C to 44.0°C

to find out

the decrease in millimeters in level

solution

we  will calculate here change in volume so we can find how much level is decrease

change in volume = β v change in temp   ...............1

here change in volume = area× height

so = \pi /4 × d² h

so we can say change in volume =  \pi /4 × d² × change in height   .......2

so from equation 1 and 2  we calculate change in height

( β(w) -β(g) )× v× change in temp = \pi /4 × d² × change in height

change in height = 4 × ( β(w) -β(g) ) v× change in temp / \pi /4 × d²

put all value here

change in height = 4 × ( 210 - 27 )(350 ) 10^{-6}× (95-44) / \pi /4 × 0.05²

change in height  is 1.664 mm

5 0
3 years ago
Who is the first president of China ?
Kitty [74]

The President is Xi Jinping

6 0
3 years ago
Read 2 more answers
The constant forces F1 = 8 + 29 + 32 N and F2 = 48 - 59 - 22 N act together on a particle during a displacement from the point A
steposvetlana [31]

Answer:

- 600 J

Explanation:

A (20, 15, 0 ) m

B (0, 0, 7) m

\overrightarrow{F_{1}}=8\widehat{i}+29\widehat{j}+32\widehat{k}

\overrightarrow{F_{2}}=48\widehat{i}-59\widehat{j}-22\widehat{k}

Net force

\overrightarrow{F}=\overrightarrow{F_{1}}+\overrightarrow{F_{2}}

\overrightarrow{F}}=\left ( 8+48 \right )\widehat{i}+\left ( 29-59 \right )\widehat{j}+\left ( 32-22 \right )\widehat{k}

\overrightarrow{F}}=56\widehat{i}-30\widehat{j}+10\widehat{k}

\overrightarrow{S}=\overrightarrow{OB}-\overrightarrow{OA}

\overrightarrow{S}=\left ( 0-20 \right )\widehat{i}+\left ( 0-15 \right )\widehat{j}+\left ( 7-0 \right )\widehat{k}

\overrightarrow{S}=-20\widehat{i}-15\widehat{j}+7\widehat{k}

Work done is defined as

W = \overrightarrow{F}.\overrightarrow{S}

W = \left ( 56\widehat{i}-30\widehat{j}+10\widehat{k} \right ).\left (-20\widehat{i}-15\widehat{j}+7\widehat{k}  \right )

W = -1120 + 450 + 70

W = - 600 J

3 0
3 years ago
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