The moon's orbital plane is different from that of the earth's orbit around the sun due to which lunar and solar eclipses do not occur every month.
<h3 /><h3>What is a solar eclipse?</h3>
When the moon passes in front of Earth and the sun, it creates a solar eclipse and casts a shadow across the globe.
Only during the new moon phase, when the moon travels squarely between the sun and Earth and casts shadows on its surface, can a solar eclipse occur.
Due to the moon's orbit being five degrees off-center from Earth's orbit around the Sun, lunar eclipses do not happen every month and the Moon often passes above or below the shadow.
Lunar eclipses would happen every month if there were no tilt. Eclipses of the sun and the moon happen equally often.
Hence lunar and solar eclipses aren't coming every month.
To learn more about the solar eclipse refer;
brainly.com/question/17749647
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Answer:
Acceleration is the rate of change of velocity. What is commonly said as ‘ten meter per second squared’ can bee broken down into ‘ten meter per second per second.’ This gives us the true meaning of the term acceleration.
Just like ‘ten meter per second’ means increasing the displacement by ten meters every second, ‘ten meter per second per second’ means increasing the velocity by ten meters per second every second.
So, basically if you consider the case of a free fall motion, where ‘t’ stands for time and ‘v’ stand for velocity at that instant:
At,
t=0, v=0 m/s
t=1, v=0+10 m/s;
t=2, v=0+10+10 m/s;
t=3, v=0+10+10+10 m/s;
This can also be thought as a Arithmetic Progression where common difference ‘D’ is the acceleration(a), since it adds a 10 m/s to velocity every second and the first term ‘A’ stands for the initial velocity (u). Using this approach we can derive to the first equation of motion:
v = u + at
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Explanation:
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Answer:
The magnetic flux through surface is
Wb
Explanation:
Given :
Magnitude of magnetic field
T
Radius of circle
m
Angle between field and surface normal
25°
From the formula of flux,


Where
angle between magnetic field line and surface normal,
area of circular surface.



Magnetic flux is given by,

Wb
Therefore, the magnetic flux through surface is
Wb
Answer:
T = 37.08 [N*m]
Explanation:
We must remember that torque is defined as the product of a force by a distance. This distance is measured from the point of application of force to the center of rotation of the rotating body.
The force is equal to the product of mass by gravitational acceleration.
![F=m*g\\F=70*9.81\\F=686.7[N]](https://tex.z-dn.net/?f=F%3Dm%2Ag%5C%5CF%3D70%2A9.81%5C%5CF%3D686.7%5BN%5D)
Now the torque can be calculated:
![T=F*r\\T=686.7*0.054\\T=37.08[N*m]](https://tex.z-dn.net/?f=T%3DF%2Ar%5C%5CT%3D686.7%2A0.054%5C%5CT%3D37.08%5BN%2Am%5D)