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rodikova [14]
3 years ago
15

¿Por qué es útil comprender tu condición física?

Physics
1 answer:
finlep [7]3 years ago
4 0

Answer:

Es útil porque al saberlo evitas sobrexponerte a problemas como <em><u>enfermedades, desgarros o daños a largo plazo de tu cuerpo.</u></em>

Explanation:

When a person decides to start exercising or some type of physical activity, it is necessary for him to know how much his body can resist that activity during a defined period of time.

If in some way or another your body does not resist physical activity, you can hurt yourself, tear a ligament or muscle or get sick.

One of the most common diseases that almost nobody notices is the increase in circulatory and heart problems.

It is best to know your physical condition, how much weight you can carry with weights, or how long you can last doing physical activities.

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Movement of air from land to sea at night, created when cooler, denser air from the land forces up warmer air over the sea.
kondaur [170]
The answer is A. LAND BREEZE
4 0
3 years ago
Read 2 more answers
A rock is suspended by a light string. When the rock is in air, the tension in the string is 51.9 N . When the rock is totally i
Luden [163]

Answer:

\rho _{liquid}=1995.07kg/m^{3}

Explanation:

When the rock is immersed in unknown liquid the forces that act on it are shown as under

1) Tension T by the string

2) Weight W of the rock

3) Force of buoyancy due to displaced liquid B

For equilibrium we have T_{3}+B = W_{rock}

T_{3}+\rho _{Liquid}V_{rock}g=W_{rock}.....(\alpha)

When the rock is suspended in air for equilibrium we have

T_{1}=W_{rock}....(\beta)

When the rock is suspended in water for equilibrium we have

T_{2} + \rho _{water}V_{rock}g=W_{rock}.....(\gamma)

Using the given values of tension and solving α,β,γ simultaneously for \rho _{Liquid} we get

W_{rock}=51.9N\\31.6+1000\times V_{rock}\times g=51.9N\\\\11.4+\rho _{liquid}V_{rock}g=51.9N\\\\

Solving for density of liquid we get

\rho _{liquid}=\frac{51.9-11.4}{51.9-31.6}\times 1000

\rho _{liquid}=1995.07kg/m^{3}

5 0
3 years ago
A small rock is thrown vertically upward with a speed of 21.0 m/sm/s from the edge of the roof of a 21.0-mm-tall building. The r
FromTheMoon [43]

Answer:

Explanation:

A.

Given:

Vo = 21 m/s

Vf = 0 m/s

Using equation of Motion,

Vf^2 = Vo^2 - 2aS

S = (21^2)/2 × 9.8

= 22.5 m.

B.

Given:

S = 22.5 + 21 mm

= 22.521 m

Vo = 0 m/s

Using the equation of motion,

S = Vo × t + 1/2 × a × t^2

22.521 = 0 + 1/2 × 9.8 × t^2

t^2 = (2 × 22.521)/9.8

= 4.6

t = 2.14 s

4 0
3 years ago
A twin-sized air mattress used for camping has dimensions of 100 cm by 194 cm by 14 cm when blown up. The weight of the mattress
Paul [167]

Answer:

2625.156\ \text{N}

Explanation:

Dimensions of mattress 100 cm by 194 cm by 14 cm

m_m = Mass of mattress = 4 kg

\rho = Density of water = 1000\ \text{kg/m}^3

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Volume of mattress

V=100\times 194\times 14=271600\ \text{cm}^3=0.2716\ \text{m}^3

Weight of water displaced is equal to the buoyant force

Mass of water

m=\rho V\\\Rightarrow m=1000\times 0.2716\\\Rightarrow m=271.6\ \text{kg}

Mass of person would be

m_p=m-m_m=271.6-4\\\Rightarrow m_p=267.6\ \text{kg}

Weight of the person would be

w=m_pg\\\Rightarrow w=267.6\times 9.81\\\Rightarrow w=2625.156\ \text{N}

The air mattress could hold a person that weighs up to 2625.156\ \text{N}.

8 0
2 years ago
The speed of light is now defined to be 2.99792458 10 m/s (a) Express the speed of light to three significant figures m/s (b) Ex
vazorg [7]

Answer:

a) 3.00×10⁸ m/s

b) 2.9979×10⁸ m/s

c) 2.997925×10⁸ m/s

Explanation:

299792458 m/s is the speed of light

Let us write this in scientific notation first

2.99792458×10⁸ m/s

a) In three significant figures

We need to round the number to the hundredths place

3.00×10⁸ m/s

b) In five significant figures

We need to round the number to the ten thousandths place

2.9979×10⁸ m/s

c) In seven significant figures

We need to round the number to the millionths place

2.997925×10⁸ m/s

8 0
3 years ago
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