The first hill of a roller coaster is 42 meters high. The top of the second hill of the one
2 answers:
Answer:
Part a)
Speed of the roller coaster is
Part b)
Since it is moving with non zero speed at some height above the ground
So we will have
Kinetic energy + Potential energy Both
Explanation:
As we know that there is no friction on the path
So here we can use mechanical energy conservation law
so we will have
Part a)
Part b)
Since it is moving with non zero speed at some height above the ground
So we will have
Kinetic energy + Potential energy Both
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at the lowest point in the trajector, the kinetic energy of the bob is 300 J.
Explanation:
The total mechanical energy of the bob at any point of its motion is given by
Where
is the kinetic energy, where
m is the mass of the bob
v is its speed
is the gravitational potential energy, where
g is the acceleration of gravity
h is the height of the bob, measured with respect to the lowest point of the trajector
In absence of friction, the total mechanical energy E remains constant. So we have:
- When the bob swings upward, the PE increases (because h increases) and the KE decreases (so the speed decreases). At the highest point in the trajector, the speed of the bob is zero (v=0), so its KE is also zero and all the mechanical energy is potential energy: U = 300 J
- When the bob swings downward, the PE decreases (because h decreases) and the KE increases (so the speed increases). At the lowest point in the trajectory, the height has become zero (h=0), so the PE is zero and all the mechanical energy is kinetic energy: KE = 300 J
Therefore, at the lowest point in the trajector, the kinetic energy of the bob is 300 J.
Learn more about kinetic energy:
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