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Vaselesa [24]
4 years ago
9

The first hill of a roller coaster is 42 meters high. The top of the second hill of the one

Physics
2 answers:
AleksAgata [21]4 years ago
8 0

Answer:

Explanation:

The first hill of a roller coaster is 42 meters high. The top of the second hill of the roller coaster is 33 meters high. The mass of the roller coaster is 34,500 kg

Marta_Voda [28]4 years ago
7 0

Answer:

Part a)

Speed of the roller coaster is

v = 13.3 m/s

Part b)

Since it is moving with non zero speed at some height above the ground

So we will have

Kinetic energy + Potential energy Both

Explanation:

As we know that there is no friction on the path

So here we can use mechanical energy conservation law

so we will have

Part a)

U_i  + K_i = U_f + K_f

mgh + 0 = \frac{1}{2}mv^2 + mgH

34500(9.81)(42) = \frac{1}{2}(34500)v^2 + 34500(9.81)(33)

v = 13.3 m/s

Part b)

Since it is moving with non zero speed at some height above the ground

So we will have

Kinetic energy + Potential energy Both

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aleksandr82 [10.1K]

Work Done (W) by the field is-6x 107 J,

<h3>What is Electric dipole?</h3>

A pair of opposite, non-coplanar, equally powerful electric charges that are in opposition to one another. An atom is said to have a "induced electric dipole" if the center of the negative cloud of electrons has moved a little bit away from the nucleus due to an external electric field. When the external field is taken away, dipolarity is lost.

Electric field (E) = 300 N/C

Dipole moment (p) = 2 x 10° Cm

Solution:

From the formula we know.

U = -pE cosФ

Here,

p Denotes Dipole moment.

E Denotes Electric field.

Ф Denotes angle b/w them

Now, as given, firstly the dipole is perpendicular to the electric field, so

angle (Ф1) will be 90° and now the dipole is rotated such that they are in same

direction so the angle (Ф2) will be 0°

So, let's find Change in Potential energy which will be equal to the work done

by the electric field.

ΔU = Uf - Ui

ΔU = [-pE*cos Ф2] - [-pE *cos Ф1]

ΔU = [-pE*cos Ф2] + pE *cos Ф1

ΔU = pE * [cos Ф2+ cos Ф1]

Substituting the values,

ΔU = pE * [cos 0° + cos 90°]

ΔU = pE * (-1 +0)

ΔU = -pE

ΔU = -2x 10^-9 × 300

ΔU = 6 x 10^(-9+2)

ΔU = 6 x 10^-7

W = ΔU = -6 x 10^-7

W = - 6 x 10 7 J

Work Done (W) by the field is - 6 x 10-7 J.

To learn more about Work Done visit:

https://brainly.in/question/48222628

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3 years ago
50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the bui
soldi70 [24.7K]

Answer:

98.13m

Explanation:

Complete question

Daniel is 50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the building

CHECK THE ATTACHMENT

From the figure, using trigonometry

Tan(θ ) = opposite/adjacent

Where Angle (θ )= 63°

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Adjacent= 50 m

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Power is your answer :)

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