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Sergeu [11.5K]
3 years ago
8

In the figure shown below, what fractional part of the circle is shaded?

Mathematics
1 answer:
Alex73 [517]3 years ago
4 0
The answer is A, 4/15.
1/3 + 2/5 = 11/15.
15/15-11/15 = 4/15. 
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Matt plans to put concrete on a rectangular portion on his driveway. The portion is 8 feet long and 4 inches high. The price of
marishachu [46]
First the cost of $98 /yd³ by the conversion factor that
1 yd³ = 27 ft³.
 ($98 /yd³) (1 yd³ / 27 ft³) = $ 3 17/27/ft³

Let x be the width, the volume of the rectangular portion of the driveway is,

 V = (8 ft) (1/3 ft) x = 8x/3 ft³

Using the given total cost of the protion,
 C = $58.07 = (8x/3 ft³)(<span>$ 3 17/27/ft³) 

x = 5.99957 ft
 the answer is  6 feet. (rounded)</span>
8 0
3 years ago
Write the following phrase as a variable expression. Use X to represent “a number.” The sum of eleven, a number, and the product
melamori03 [73]

Answer:

11 + x + 19*x

Step-by-step explanation:

The sum of eleven, a number, and the product of nineteen and the number.

we have to read carefully and understand how to interpret

when he says the sum of separates into 3 parts because there is a "comma" and an "and"

Now let's separate the 3 parts of the sum

1 part

says eleven so we just put 11

eleven = 11

2 part

in the text it says that we replace "a number" with x

a number = x

3 part

In this case we simply make the product between the given values

the product of nineteen and the number

19 * x

Now we can accommodate everything and we finish

11 + x + 19*x

6 0
3 years ago
Which pair of addenda has sun of 0?
alexandr402 [8]

Answer:

-5 and 5.

Step-by-step explanation:

Subtracting 5 from 5, leads to 0 as the final answer.

I hope this  helps! :)

7 0
2 years ago
Read 2 more answers
The amount of bacteria in a petri dish increases at a rate proportional to the amount present. At time t=0, the amount of bacter
Lilit [14]

Answer:

Step-by-step explanation:

Formula to be used is N=N0e^(kt)

N0 - amount of bacteria at time 0, which is 10g

t=2, 30g

30 = 10*e^(k*2)

3 = e^(2k)

2k = ln3

k = 0.5ln3

At t=6:

N = 10*e^(0.5ln3*6)

N = 10e^(3ln3)

N = 10e^ln27

N = 10*27 =270

So the amount of bacteria at t=6 is 270

6 0
3 years ago
Help me please I need an an answer asap
storchak [24]
5A + 7 = 3A + 7 + 2A
We need to solve for A.

3A + 7 + 2A = 3A + 2A + 7 = 5A + 7 (We can add 3A and 2A because it's the same variable, so we add the coefficients)

5A + 7 = 3A + 7 + 2A
5A + 7 = 5A + 7

5A + 7 is always equal to 5A + 7 because it's the same equation. So the equation got infinitely many solutions.
4 0
3 years ago
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