Answer:
133.33g
Step-by-step explanation:
Let the:
Mass of 1.2g/cm³ of liquid = x
Mass of 1.8g/cm³ of liquid = y
From our Question above, our system of equations is given as:
x + y = 400........ Equation 1
x = 400 - y
1.2 × x + 1.8 × y = 1.6 × 400
1.2x + 1.8y = 640..... Equation 2
We substitute, 400 - y for x in Equation 2
1.2(400 - y) + 1.8y = 640
480 - 1.2y + 1.8y = 640
- 1.2y + 1.8y = 640 - 480
0.6y = 160
y = 160/0.6y
y = 266.67 g
Solving for x
x = 400 - y
x = 400 - 266.67g
x = 133.33g
Therefore, the mass of the liquid of density 1.2g/cm³ is 133.33g
Answer:
I think it is (x^2+9) x (x-1) x (x+1)
Step-by-step explanation:
(not sure if right but had a go)
Answer: f(x^-1) = x/5 - 3/5
Step-by-step explanation:
1. Replace f(x) with y
2. Swap the positions of x and y to make x = 5y + 3
3. Solve for y by subtracting 3 from both sides and dividing each side by 5
Answer:
t = (p^2/mn) - 1/n
Step-by-step explanation:
Here, we want to make t the subject of the formula
we start by equating both sides so as to remove the root
we have this as;
m(t + n)/t = p^2
m(t + n) = tp^2
mt + mn = tp^2
mn = tp^2 - mt
mn = t(p^2-m)
t = (p^2 - m)/mn
t = p^2/mn - 1/n