1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lakkis [162]
3 years ago
9

Alexis cell phone company charges her $35 a month for phone service plus $0.40 for each text message. How many text message does

Alexis send in a month if her bill was $72?
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer:

$92.50

Step-by-step explanation:

$72 - $35 = 37

37 / 0.40 = 92.5

Answer = $92.50

You might be interested in
Find the surface area
mote1985 [20]

Answer:

Step-by-step explanation:

l = 7 in

w = 11 in

h = 5 in

Surface area = 2*(lw +wh +hl)

        = 2*(7*11 + 11*5 + 5*7)

       = 2* (77+ 55 + 35)

     = 2 * 167

     = 334 square inches

3 0
3 years ago
Read 2 more answers
When doctors prescribe medicine, they must consider how the drug’s effectiveness declines as time passes. If each hour a drug is
Pie

Answer:

B)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
1. Nancy is purchasing a $200 coat at 15% off. What is the total amount<br> Nancy must pay?
ozzi
200 * 0.15 = $30 off
200-30 = $170
Nancy must pay $170
3 0
3 years ago
Read 2 more answers
When using substitution to solve this system of equations
dlinn [17]
Hello, find the work out in the attached image
X = 4.5
Y = -1

3 0
2 years ago
Prove the identity secxcscx(tanx+cotx)=2+tan^2x+cot^2x
svetlana [45]
Hello,

sec(x)= \dfrac{1}{cos(x)} \\&#10;&#10;cosec(x)= \dfrac{1}{sin(x)} \\&#10;&#10;sec(x)*cosec(x)*(tg(x)+cotg(x))=\dfrac{1}{cos(x)}* \dfrac{1}{sin(x)}*( \frac{sin(x)}{cos(x)} +\frac{cos(x)}{sin(x)})\\&#10;&#10;= \dfrac{sin^2(x)+cos^2(x)}{sin^2x*cos^2x} \\&#10;&#10;= \dfrac{1}{sin^2x*cos^2x} \\&#10;&#10;
==============================================================
2+tg^2(x)+cotg^2(x)=2+ \dfrac{sin^2x}{cos^2x} + \dfrac{cos^2x}{sin^2x} \\&#10;&#10;=2+ \dfrac{sin^4x+cos^4x}{sin^2x*cos^2x} \\&#10;&#10;=\dfrac{2*sin^2x*cos^2x+sin^4x+cos^4x}{sin^2x*cos^2x} \\&#10;&#10;= \dfrac{(sin^2x+cos^2x)^2}{sin^2x*cos^2x}} \\&#10;&#10;= \dfrac{1}{sin^2x*cos^2x}} &#10;
8 0
3 years ago
Read 2 more answers
Other questions:
  • Please answer this . It’s of class 8 Thank you
    13·2 answers
  • I need help with this. ASAP
    15·2 answers
  • Where does 0.5 go on a graph
    8·2 answers
  • Find the sum of the three expressions and choose the correct answer.
    8·2 answers
  • To find the height of a pole, a surveyor moves 140 feet away from the base of the pole and then, with a transit 4 feet tall, mea
    13·1 answer
  • Can someone help please
    8·1 answer
  • Calculate the area of a circle with the radius of 2cm. Pie=3
    14·2 answers
  • Simplify the expression. 5(z+4)+5(2−z)
    12·1 answer
  • 2.5x=-10 what is the answer
    9·2 answers
  • Footware manufacturing is projected to decrease output by 8.4% from 2006 to 2016. if footware manufacturing had 1.8 billion doll
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!