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lesya [120]
4 years ago
13

What is the GCF of 250 and 50

Mathematics
1 answer:
nalin [4]4 years ago
6 0
GCF = 50



Just search it on google...






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A number cube is rolled 14 times and the results are recorded in the table.
marshall27 [118]

Answer:

D.5/14

Because 4 appeared five times over the total

8 0
2 years ago
What are two solutions of 3 + 4 |x/2 + 3| = 11?
Alex
3 + 4abs(x/2 + 3) = 11 Subtract 3
4 abs(x/2 + 3) = 11 - 3
4 abs(x/2 + 3) = 8 Divide by 4
abs(x/2 + 3) = 8/4
abs(x/2 + 3) = 2

Solution 1
x/2 + 3 = 2 Subtract 3
x/2 = 2 - 3
x/2 = - 1 Multiply by 2
x/2 *2 = - 2
x = - 2

Solution 2
x/2 + 3 = - 2
x/2 = - 2 - 3
x/2 = - 5 Multiply by 2
x = -5 * 2
x = -10

Solutions
x = - 2 <<<< answer 1
x = -10 <<<< answer 2

3 0
4 years ago
Solve the equation for the specified variable <br> Y=cd-8, for c
melomori [17]
Y=cd-8
Add 8 to each side giving you
y+8=cd

Divide by d on each side giving you

C=(y+8)/d
8 0
3 years ago
How do I solve for y:<br> x²y² = 12/z²
Vika [28.1K]

Answer:

Y=Srt(12xs^2/z^2)

Step-by-step explanation:

Firstly

We multiply both sides with 1/x^2

We get

Y^2=12/z^2*1/x^2

Y^2=12x^2/z^2

Next: introduce a srt root

We have

Y=srt(12x^2/z^2)

8 0
3 years ago
A tobacco company claims that the amount of nicotine in its cigarettes is a randomvariable with mean 2.2 mg and standard deviati
Genrish500 [490]

Answer:

0.0000

Unusual

Step-by-step explanation:

Given that a tobacco company claims that the amount of nicotine in its cigarettes is a random variable with mean 2.2 mg and standard deviation .3 mg.

i.e. population parameters are

\mu =2.2 \\s = 0.3

The approximate probability that the sample meanwould have been as high or higher than 3.1

=P(X\geq 3.1)\\=P(Z\geq \frac{3.1-2.2}{\frac{0.3}{\sqrt{100} } } )\\=P(Z\geq 30)\\

=0.0000

8 0
3 years ago
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