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elena-14-01-66 [18.8K]
3 years ago
15

How do I solve for y: x²y² = 12/z²

Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

Y=Srt(12xs^2/z^2)

Step-by-step explanation:

Firstly

We multiply both sides with 1/x^2

We get

Y^2=12/z^2*1/x^2

Y^2=12x^2/z^2

Next: introduce a srt root

We have

Y=srt(12x^2/z^2)

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<u>Final Answer:</u>

x = 20

<u>Step-by-step explanation:</u>

we'll be using the pythagorean theorem method, in this triangle the missing letter is a.

formula: a=\sqrt{c^2-b^2}

a = x

b = 21

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a = \sqrt{29^2-21^2}

a = \sqrt{841-441}     (note: 29² = 29 × 29 = 841 and 21² = 21 × 21 = 441)

a = \sqrt{400}

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3 years ago
What is the value of x????
inysia [295]

If QR is a median, then:

\dfrac{NO+MP}{2}=QR

We have NO = 30, MP = 9x - 42 and QR = x + 15. Substitute:

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In triangle ABC m <br> A.47<br> B.109<br> C.114<br> D.71
sashaice [31]

Answer:

71

Step-by-step explanation:

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3 years ago
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3 years ago
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