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elena-14-01-66 [18.8K]
3 years ago
15

How do I solve for y: x²y² = 12/z²

Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

Y=Srt(12xs^2/z^2)

Step-by-step explanation:

Firstly

We multiply both sides with 1/x^2

We get

Y^2=12/z^2*1/x^2

Y^2=12x^2/z^2

Next: introduce a srt root

We have

Y=srt(12x^2/z^2)

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Which expression can you simplify by combining like terms?
omeli [17]

Answer:

The correct option is A.

Step-by-step explanation:

If the degree and variables of two terms are same, then they are called like terms.

In option A.

The given expression is  

12b^2+4ab-3ba-6

Here, 4ab and -3ab are like terms because both have same variables a and b with degree 1.

By combining like terms we get

12b^2+(4ab-3ab)-6

12b^2+ab-6

In options B, C and D, there are no like terms, So only the expression 12b^2+4ab-3ba-6 we can simplify by combining like terms.

Therefore the correct option is A.

7 0
3 years ago
V-10=-3 solve the equation
Evgesh-ka [11]

Answer:

v =7

Step-by-step explanation:

Simplifying

v + -10 = -3

Reorder the terms:

-10 + v = -3

Solving

-10 + v = -3

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '10' to each side of the equation.

-10 + 10 + v = -3 + 10

Combine like terms: -10 + 10 = 0

0 + v = -3 + 10

v = -3 + 10

Combine like terms: -3 + 10 = 7

v = 7

Simplifying

v = 7

7 0
3 years ago
Question 3
crimeas [40]

Answer:

D = 141

Step-by-step explanation:

The given quadratic equation is

5x^2+9x=3\\\\5x^2+9x-3=0.

It is required to find the value of the discriminant. The value of discriminant  of any quadratic equation is given by :

D=b^2-4ac

Here, a = 5, b = 9 and c = -3

On plugging all the values, we get :

D=(9)^2-4\times 5\times (-3)\\\\D=141

So, the value of discriminant for y is 141.

8 0
2 years ago
Use benchmark values to estimate 7/10 + 7/8.​
allsm [11]

Answer:

1.575

Step-by-step explanation:

4 0
3 years ago
What is the domain range and zeros of the graph ?
marusya05 [52]

The domain is how far the graph stretches horizontally (on the x-axis).

Domain:  ( -∞ , ∞ )  or  -∞ < x < ∞

The range is how long the graph stretched vertically (on the y-axis).

Range:  ( -∞ , 2 ]  or  -∞ < y ≤ 2

The zeros are where the graph intersects with the x-axis. In other words, the x-values when y=0.

Zeros:  x = -1  and  x = 3

8 0
3 years ago
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