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max2010maxim [7]
3 years ago
12

What is the constant proportionality in the equation 3 y=2x

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0

Answer:

2

Step-by-step explanation:

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In need of some help please.
Hatshy [7]
By the Pythagorean theorem
  50^2 = x^2 +(x +34)^2
  2500 = 2x^2 +68x + 1156
  x^2 +34x -672 = 0
  (x -14)(x +48) = 0
  x = 14 or -48

The distance from the wall to the base of the ladder is 14 ft.

_____
7-24-25 is a Pythagorean triple. The dimensions here are double those values. It can be handy to know a few of the Pythagorean triples, as that can let you write down the answers to problems without having to go through the equations.
8 0
3 years ago
Find the value (18 9) / 3d for d=3
Alexeev081 [22]
Assuming that you ment- (18*9)/3d where d=3 you would follow PEMDAS-
Parentheses
Exponents
Multiplication-Division (in order from right to left)
Addition-Subtraction (in order from right to left)
1. Parentheses- (18*9)=162
2. Solve your variables- 3d (3*3)=9
Giving you- 162/9
3. Solve-162/9=18
7 0
3 years ago
R 0,60 is the same rotation as Ro,<br> -300<br> 120<br> 300
Orlov [11]
The answer is the last one 300
3 0
3 years ago
Read 2 more answers
Write a equation of a hyperbola given the foci and the asymptotes
professor190 [17]

Solution:

The standard equation of a hyperbola is expressed as

\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}

The asymptote of n hyperbola is expressed as

y=\pm\frac{a}{b}(x-h)+k

Given that the asymptotes are

y=\frac{3}{4}x\text{ and y=-}\frac{3}{4}x

This implies that

a=3,\text{ and b=4}

To evaluate the value of h and k,

undefined

3 0
1 year ago
Anyone know this answer?
damaskus [11]
La of sine:

sinC/c = sinB/b==> sin  37°/8 = sin B/12 ==> sin B = 0.903


arcsinB or sin⁻¹ B = 64.5°, & sin (B°) = sin (180° - B°), then

sin(64.5) = sin(180°-64.5°) ==> B = 64.5° or 115.5°
6 0
3 years ago
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