All categories

3 years ago

Hi I need help on this!!

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

8 0

Answer:

VOLUME OF THE CYLINDER=πr²h

=3.14×4²×9

=3.14×16×9

=452.16 mm³

You might be interested in

Which of these drawings show ab parallel the cd perpendicular to ef?

Sergio039 [100]

Where's the drawing?

6 0

3 years ago

Please do this ASAP!<br> No links !

Andreas93 [3]

Answer:

2100

Step-by-step explanation:

28.34 rounds to 30

We look at the 8 which is greater than 5 and rounds the 2 to 3

69.72 rounds to 70

We look at the 9 which is greater than 5 and rounds the 6 to 7

30*70

2100

7 0

3 years ago

− 3 − {3 − [ − 3(2 +4) − ( − 2)]}

Readme [11.4K]

-22 is the answer i got

4 0

3 years ago

What is the solution to the inequality?<br><br> 6x − 5 > −29

juin [17]

X > -4 is the answer to the inequality

8 0

4 years ago

Read 2 more answers

The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Ivenika [448]

Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

$AV = \frac{y(t2) - y(t1)}{t2 - t1}$

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

$AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6$

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

$AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8$

So the average speed is -128.9 ft/s

iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

$AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16$

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

3 0

3 years ago