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Norma-Jean [14]
3 years ago
7

Find three consecutive even integers such that the sum of twice the smallest number and three times the largest is 42.

Mathematics
1 answer:
Otrada [13]3 years ago
7 0
The difference between two consecutive integers is 2.
Let n be the smallest of the three even integers.
Then the next larger even integer is n + 2.
The largest even integer is n + 4.
Now we follow what the problem tells us.

Twice the smallest is 2n
3 times the larges is 3(n + 4)

2n + 3(n + 4) = 42

2n + 3n + 12 = 42

5n + 12 = 42

5n = 30

n = 6

n + 2 = 8

n + 4 = 10

The integers are 6, 8, 10
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The sum of two numbers is 21. The larger number is 6 less than twice the smaller number. Find the two numbers.
Semenov [28]
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6 0
3 years ago
Rectangle
eduard

Options A and D are correct. The pair of measurements that could be the dimensions of rectangle B is 6 cm by 1.5 cm and 18 cm by 4.5 cm.

For us to get a scale copy of the dimension, we need to first find the scale factor as shown;

Given the measure of rectangle A:

  • Length= 12cm
  • Width = 3cm

To get all of the measurement pairs that could be the dimensions of Rectangle  B, we need to multiply the length and width by the same factor

Multiplying by 1/2

New length = 12 × 0.5 = 6cm

New width = 3 × 0.5 = 1.5cm

Hence 6cm by 1.5cm can be dimension of B

Multiplying by 1.5

New length = 12 × 1.5 = 18cm

New width = 3 × 1.5 = 4.5cm

Hence 18cm by 4.5cm can be dimension of B

Learn more here: brainly.com/question/24759485

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saveliy_v [14]

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