Answer:
The third particle should be at 0.0743 m from the origin on the negative x-axis.
Explanation:
Let's assume that the third charge is on the negative x-axis. So we have:
We know that the electric field is:
Where:
So, we have:
Let's solve it for r(3).
Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.
I hope it helps you!
Answer:
The pickup truck and hatchback will meet again at 440.896 m
Explanation:
Let us assume that both vehicles are at origin at the start means initial position is zero i.e. = 0. Both the vehicles will cross each other at same time so we will make equations for both and will solve for time.
Truck:
= 33.2 m/s, a = 0 (since the velocity is constant),
= 0
Using
s = 33.2t .......... eq (1)
Hatchback:
,
= 0 m/s (since initial velocity is zero),
= 0
Using
putting in the data we will get
now putting 's' value from eq (1)
which will give,
t = 13.28 s
so both vehicles will meet up gain after 13.28 sec.
putting t = 13.28 in eq (1) will give
s = 440.896 m
So, both vehicles will meet up again at 440.896 m.
Answer
given,
flow from the artery = 3.5 x 10⁻⁶ m³/s
Radius of artery = 5.80 x 10⁻³m
area = π R²
= π x (5.8 x 10⁻³)²
= 1.06 x 10⁻⁴ m²
v = 0.033 m/s
b) new velocity of flow
Radius = R' = R/4
A V = A' V'
R² V = R'² V'
R^2 V = (\dfrac{R}{4})^2 V'
V' = 16 V
V' = 16 x 0.033
V' =0.528 m/s