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3 years ago

What happens to the force needed to stretch a rubber band when putting it on a stack of papers?

Physics

2 answers:

zmey [24]3 years ago

4 0

Answer:the force is needed to stretch it farther.

Explanation: the definition of force is push or pull so imagine stretching a rubber band your pulling the band which means you increase the force.

Ainat [17]3 years ago

3 0

Answer:

The rubber band works as a spring, so the force that you need to stretch it would be equal to:

F = X*k where X is the change in the perimeter of the rubber band and k is a constant of the rubber band.

So you need to apply force to stretch it, and when you put it again in the stack of papers, the stack of papers applies a normal force against the rubber band that keeps the rubber band a little bit stretched.

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An exoplanet with one half of Earth's mass and 50% of Earth's radius is discovered.

Georgia [21]

Answer:

The space cadet that weighs 800 N on Earth will weigh 1,600 N on the exoplanet

Explanation:

The given parameters are;

The mass of the exoplanet = 1/2×The mass of the Earth, M = 1/2 × M

The radius of the exoplanet = 50% of the radius of the Earth = 1/2 × The Earth's radius, R = 50/100 × R = 1/2 × R

The weight of the cadet on Earth = 800 N

$The \ weight, W =G\dfrac{M \times m}{R^{2}} = 800 \ N$

Therefore, for the weight of the cadet on the exoplanet, W₁, we have;

$W_1 =G\dfrac{\dfrac{M}{2} \times m}{ \left ( \dfrac{R}{2} \right ) ^{2}} = G\dfrac{\dfrac{M}{2} \times m \times 4}{ R ^{2}} = 2 \times G \times \dfrac{M \times m}{R^{2}} = 2 \times 800 \, N = 1,600 \, N$

The weight of a space cadet on the exoplanet, that weighs 800 N on Earth = 1,600 N.

7 0

3 years ago

Solar energy leaves the core of the sun in the form of

olasank [31]

photons and convection - density differences makes bubbles of hot stuff float up. pretty sure

3 0

3 years ago

Strontium chloride, SrCl2<br> Is ionic or covalent

Cloud [144]

Answer:

it is a ionic bond because electrons are transferred from chlorine to strontium

5 0

2 years ago

Read 2 more answers

A sound is produced at one extremity of a metallic pipe of 1000 m of length. A person being at

prohojiy [21]

The sound was repeated because of the phenomenon of echo. The speed of sound in the metal is 800 m/s.

Echo results from the reflection of sound waves. The reason why a sound may be heard twice owes to the phenomenon of reflection which leads to echo.

To determine the speed of sound in the metal;

Length of metal = 1000 m

Time taken between the two sounds = 2.5 s

Using the formula;

V = 2d/t

V = 2(1000)/2.5

V = 800 m/s

6 0

2 years ago

In a typical golf swing the club is in contact with the ball for about 0.0010 s. If the .045 kg ball experiences a force of 4000

Musya8 [376]

Answer:

v = 88.89 [m/s]

Explanation:

To solve this problem we must use the principle of conservation of momentum which tells us that the initial momentum of a body plus the momentum added to that body will be equal to the final momentum of the body.

We must make up the following equation:

$F*t = m*v$

where:

F = force applied = 4000 [N]

t = time = 0.001 [s]

m = mass = 0.045 [kg]

v = velocity [m/s]

$4000*0.001=0.045*v\\v=88.89[m/s]$

5 0

3 years ago