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Greeley [361]
3 years ago
6

Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11

Physics
1 answer:
Svetlanka [38]3 years ago
6 0

Answer:

a)The correct answer is option X

b)The correct answer is option Z

Explanation:

For question 3 -

When the 2 waves interfere , they add up at all the points

Since the 2 waves have 0 phase difference (as seen from the diagram) , the resultant wave also has 0 phase difference.

The amplitude of 2 waves will simply add up -

A_{1} = 1

A_{2} = 0.5

∴A_{net} = A_{1} + A_{2} = 1.5

The resultant wave should also have 0 displacement at origin.

∴The correct answer is option X

For question 35 -

The 2 waves are out of phase by 180°

∴ The amplitude of two waves would simply get subtracted -

A_{1} = 1

A_{2} = 1

∴A_{net} = A_{1} - A_{2} = 0

Since the amplitude is 0 the displacement of wave would be 0 at every point.

∴ The correct answer is option Z

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A tennis ball is thrown from a 25 m tall building with a zero initial velocity. At the same moment, another ball is thrown from
Nataly [62]

Answer:

The two balls meet in 1.47 sec.

Explanation:

Given that,

Height = 25 m

Initial velocity of ball= 0

Initial velocity of another ball = 17 m/s

We need to calculate the ball

Using equation of motion

s=ut+\dfrac{1}{2}gt^2+h

Where, u = initial velocity

h = height

g = acceleration due to gravity

Put the value in the equation

For first ball

s_{1}=0-\dfrac{1}{2}gt^2+25....(I)

For second ball

s_{2}=17t-\dfrac{1}{2}gt^2+0....(II)

From equation (I) and (II)

-\dfrac{1}{2}gt^2+25=17t-\dfrac{1}{2}gt^2+0

t=\dfrac{25}{17}

t=1.47\ sec

Hence, The two balls meet in 1.47 sec.

6 0
4 years ago
The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the magnitude of the
PIT_PIT [208]

The drag force is directly proportional to the square of the velocity of motion of the object. So as the speed is doubled, the magnitude of drag force will get quadrupled.

<u>Explanation: </u>

Drag force is the opposing or resisting force acting on any object by the medium in which it is moving. So in this case, you are riding a bicycle, thus the medium can be considered as air.

The formula for calculating drag force is as below:

               \text {Drag force }=\frac{1}{2} \rho v^{2} C_{D} A

Here, ρ is the density of the air molecules, v is the velocity or speed of the bicycle, CD is the drag coefficient and A is the area of the bicycle.

In the above equation, only the term velocity will be a varying quantity with respect to time and other quantities will remain constant throughout the single situation of riding of bicycle.

So, the equation can be,

             \text { Drag force }=k v^{2}

Where ,  

     k=\frac{1}{2} \rho C_{D} A (constant for this whole condition)

Now given the speed of bicycle increased from v to 2v, so the initial drag force will be

                   N_{i}=k v^{2}

After increase in speed, the final drag force will be  

                   N_{f}=k(2 v)^{2}

                   N_{f}=4 k v^{2}=4 N_{i}

Thus, if the speed of the bicycle is doubled, the drag force will get increased by four times.

4 0
3 years ago
In the year 1178, five monks at Canterbury Cathedral in England observed what appeared to be an asteroid colliding with the moon
Contact [7]

Complete Question

In the year 1178, five monks at Canterbury Cathedral in England observed what appeared to be an asteroid colliding with the moon, causing a red glow in and around it. It is hypothesized that this event created the crater Giordano Bruno, which is right on the edge of the area we can usually see from Earth.

How long after the asteroid hit the Moon,which is 3.84 *10^5 km away ,would the light first arrive on the earth in seconds

Answer:

The time it would take is  t = 1.28 \ sec

Explanation:

The objective of this question is to obtain the time the light would arrive earth

      We are told that the distance from moon to  earth is  

                  D = 3.84*10^5km = 3.84*10^5 * 1000 = 3.84*10^8m

Now generally time is mathematically represented as

                          t = \frac{D}{c}

The c here is the speed of light which has a value of c = 3*10^8 m/s

        Now substituting values

                        t = \frac{3.84 * 10^8 }{3*10^8}

                           = 1.28 \ sec

7 0
3 years ago
Read 2 more answers
The classic Millikan oil-drop experiment was the first to obtain an accurate measurement of the charge on an electron. In it, oi
Sati [7]

Answer:

1.56\times 10^5 N/C        

Explanation:

The electric field that will balance the weight of the oil drop can be calculated using the following:

electric force, F = e E ( where, e is the charge of an electron and E is the electric field)

weight, W = 2.5 ×10⁻¹⁴ N

e E = W

E =\frac{W}{e}

Substitute the values:

E =\frac{ 2.5 \times 10^{-14} N}{1.6\times10^{-19}C}= 1.56\times 10^5 N/C

6 0
3 years ago
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A parallel-plate capacitor is connected to a battery. What happens to the stored energy if the plate separation is doubled while
marta [7]

Answer:

(c)  As 'd' becomes doubled, energy decreases by the factor of 2

Explanation:

Energy stored in a parallel plate capacitor is given by:

U=\frac{1}{2}CV^2\\\\C=\frac{A\epsilon_{o}}{d}\\\\then\\\\U=\frac{1}{2}\frac{A\epsilon_{o}}{d}V^2--(1)\\\\

As capacitor remains connected to the battery so V remains constant. As can be seen from (1) that energy is inversely proportional to the separation between the plates so as 'd' becomes doubled, energy decreases by the factor of 2.

3 0
4 years ago
Read 2 more answers
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