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Greeley [361]
3 years ago
6

Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11

Physics
1 answer:
Svetlanka [38]3 years ago
6 0

Answer:

a)The correct answer is option X

b)The correct answer is option Z

Explanation:

For question 3 -

When the 2 waves interfere , they add up at all the points

Since the 2 waves have 0 phase difference (as seen from the diagram) , the resultant wave also has 0 phase difference.

The amplitude of 2 waves will simply add up -

A_{1} = 1

A_{2} = 0.5

∴A_{net} = A_{1} + A_{2} = 1.5

The resultant wave should also have 0 displacement at origin.

∴The correct answer is option X

For question 35 -

The 2 waves are out of phase by 180°

∴ The amplitude of two waves would simply get subtracted -

A_{1} = 1

A_{2} = 1

∴A_{net} = A_{1} - A_{2} = 0

Since the amplitude is 0 the displacement of wave would be 0 at every point.

∴ The correct answer is option Z

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An object has a position given by the radius vector r = [2.0 m + (3.00 m/s)t](i)+ [3.0 m - (2.00 m/s^2)t^2](j). Here (i) and (j)
jenyasd209 [6]

Answer:

The speed of the object is (3i - 4.00tj)m/s

The magnitude of the acceleration is 4.00m/s²

Explanation:

Given - position vector;

r = (2.0 + 3.00t)i + (3.0 - 2.00t²)j       -------------------(i)

To get the speed vector (v), take the first derivative of equation (i) with respect to time t as follows;

v = \frac{dr}{dt}

 v = \frac{d[(2.0 + 3.00t)i + (3.0 - 2.00t^2)j]  }{dt}  

v  = 3i - 4.00tj      ------------------------(ii)

To get the acceleration vector (a), take the first derivative of the speed vector in equation(ii) as follows;

a = \frac{dv}{dt}

a = \frac{d(3i - 4.00tj)}{dt}

a = -4.00j

The magnitude of the acceleration |a| is therefore given by

|a| = |-4.00|

|a| = 4.00 m/s²

In conclusion;

the speed of the object is (3i - 4.00tj)m/s

the magnitude of the acceleration is 4.00m/s²

3 0
3 years ago
Acid rain is the direct result of acid released by burning fossil fuels. T/F
disa [49]

Answer : False.

Explanation : Acid rain is the indirect result of burning fossil fuels. As the incomplete combustion of fossil fuels releases sulfur dioxide and nitrous dioxide in the air. When it rains it gets mixed with water and forms nitric acid and sulfuric acid which causes acid rain. Acid rain is harmful.

7 0
3 years ago
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A car battery seems to be malfunctioning (not providing the proper voltage and current to start your car). While the car is off
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3 years ago
URGENT
Advocard [28]

Answer:

give \\ mass(m) = 1350kg  \\ acceleration(a) = 1ms {}^{ - 2}  \ \\ sln\ \\  from \: our \: formula \\  \: f = ma \\1350kg \times 1ms {}^{ - 2}  \\ f = 1350newton

the force you applied to your car =1350N

5 0
3 years ago
An insulated thermos contains 106.0 cm3 of hot coffee at a temperature of 80.0 °C. You put in 11.0 g of ice cube at its melting
Andrei [34K]

Answer:

the final temperature is T f = 64.977 ° C≈ 65°C

Explanation:

Since the thermus is insulated, the heat absorbed by the ice is the heat released by the coffee. Thus:

Q coffee + Q ice = Q surroundings =0 (insulated)

We also know that the ice at its melting point , that is 0 °C ( assuming that the thermus is at atmospheric pressure= 1 atm , and has an insignificant amount of impurities ).

The heat released by coffee is sensible heat : Q = m * c * (T final - T initial)

The heat absorbed by ice is latent heat and sensible heat : Q = m * L + m * c * (T final - T initial)

therefore

m co * c co * (T fco - T ico) + m ice * L + m ice * c wat  * (T fwa - T iwa) = 0

assuming specific heat capacity of coffee is approximately the one of water c co = c wa = 4.186 J/g°C and the density of coffee is the same as water

d co = dw = 1 gr/cm³

therefore m co = d co * V co = 1 gr / cm³ * 106 cm³ = 106 gr

m co * c wat * (T f  - T ico) + m ice * L + m ice * c wat  * (T f - T iwa) = 0

m co * c wat * T f+ m ice * c wat  * T f  = m ice * c wat  * T iwa  + m co * c wat * Tico -m ice * L

T f  = (m ice * c wat  * T iwa  + m co * c wat * Tico -m ice * L ) /( m co * c wat * + m ice * c wat )

replacing values

T f = (11 g * 4.186 J/g°C * 0°C +  106 g * 4.186 J/g°C*80°C - 11 g * 334 J/gr) / ( 11 g * 4.186 J/g°C +  106 g * 4.186 J/g°C* ) = 64,977 ° C

T f = 64.977 ° C

7 0
3 years ago
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