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ivann1987 [24]
2 years ago
6

You are researching a fungus that can kill banana plants. Which source is

Physics
1 answer:
vladimir1956 [14]2 years ago
7 0

Answer:

B

Explanation:

what could i say except ur welcome

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Why was the Battle of the Bulge significant?
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The Battle of the Bulge in the winter of 1944 was the last Great German offensive of the Second World War.
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Two electrons, each with mass mmm and charge qqq, are released from positions very far from each other. With respect to a certai
lana66690 [7]

The answer & explanation for this question is given in the attachment below.

3 0
3 years ago
A carton is given a push across a horizontal, frictionless surface. The carton has a mass m, the push gives it an initial speed
sammy [17]

Answer and Explanation:

Data provided in the question

Carbon mass = m

Initial speed = v_i

Coefficient = μk

Based on the above information, the expressions are as follows

a. By using the energy considerations the expression for the carton moving distance is

As we know that

Fd = \frac{1}{2} m (v_i^2- v_f^2)

where,

v_f = 0

F = u_kmg

(\mu_kg) d = \frac{1}{2} m v_i^2

d = \frac{\frac{1}{2}v_i^2}{\mu_kg}

d = \frac{v_i^2}{2 \mu_kg}

b. The initial speed of the carton if the factor of 3 risen, so the expression is

v_i^1 = 3v_i

d^i = \frac{(3v_i^2)}{2\mu_kg}

= \frac{9v_i^2}{2\mu_kg}

d^i = 9(d)

8 0
3 years ago
A car speeds up from 12.0 m/s to 16.0 m/s in 8.0 s. the acceleration of the car is?
maria [59]

Vi=12m/s Vf=16m/s t=8s a=? a=Vf-Vi/t=16-12/8=4/8=1/2 a=0.5m/s^2

6 0
2 years ago
How much work do you do on a 15 N book in lifting it straight up for a distance of<br> 0.40 meters?
astra-53 [7]

Answer:

Work done, W = 6 J

Explanation:

It is given that,

Force of gravity acting on the book, weight of the book is 15 N

We need to find the work done in lifting the book straight up for a distance of  0.4 meters.

The weight of the book is acting in downward direction and the book is lifted straight up, it means angle between them is 180 degrees. Work done is given by :

W=Fd\cos180\\\\W=15\times 0.4\times \cos180\\\\W=-6\ J

So, the magnitude of work done in lifting the book is 6 joules.

7 0
3 years ago
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