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const2013 [10]
3 years ago
5

Drag each label to the correct location on the Punnett square. The Punnett square illustrates a cross for flower position in the

pea plant. The phenotypes and genotypes of the parents have been given. The allele for axial position is dominant and represented by A. The allele for terminal flower position is recessive and represented by a. What is the genotype of the offspring? Heterozygous homozygous recessive homozygous dominant
Biology
2 answers:
Minchanka [31]3 years ago
7 0

Hello :3 :3

Your question is related to genetics.

Taking a look at your question, A is dominant and axial, while a is recessive and terminal.

If you cross-breed these two pea plants, and you drew the Punnett square, you would end up with Aa (100%) heterozygous on the F1 generation.


Now, on the F2 generation, you would end up with                                                                                                     AA (25%) - Aa (50%) - aa (25%).  AA is homozygous dominant, Aa is heterozygous, and aa is homozygous recessive.


kogti [31]3 years ago
5 0

Answer: Based on the phenotypes and genotypes of these offspring, it is clear that the purple flower color allele is DOMINANT and the parents are HOMOZYGOUS RECESSIVE.

Explanation:

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Single stranded with a helix shape
slega [8]

Answer:

Both A and B

Explanation:

Because RNA is single stranded and the DNA has a helix shape

5 0
2 years ago
A biology student caught and tagged 50 trout in a small lake. After two weeks, the student caught another 40 trout and found tha
Vlad1618 [11]

The best estimate of the population of trout in the lake is 500 individuals.

The low number of tagged trout recaptured may be because the tags slipped off.

This possibility can be reduced if the student used tags that does not slip off easily.

<h3>Mark and recapture method</h3>

The formula for calculating the estimated number of individuals in the population is given as:

  • N = (M*C) / R

where:

  • N = estimated Number of individuals in the population
  • M = number of individuals captured and Marked
  • C = total number Captured the second time (with and without a mark)
  • R= number of individuals Recaptured (those with a mark)

Calculating the estimate trout population:

N = (50*40)/4

N = 50

Therefore, the best estimate of the population of trout in the lake is 500 individuals.

The low number of tagged trout recaptured may be because the tags slipped off.

This possibility can be reduced if the student used tags that does not slip off easily.

Learn more about mark and recapture method at: brainly.com/question/10646744

6 0
2 years ago
Which of the following reasons explains a possible advantage of using adult stem cells in therapeutic cloning rather than embryo
denis23 [38]
The answers are A and d
6 0
3 years ago
the graph demonstrates the quantitative variation for skin pigmentation. which conclusion is supported by the graph? a)more than
BartSMP [9]

Answer : Option D) Fewer people have skin pigmentation lighter than the central peak than people who have pigmentation darker than the central peak.

Explanation : The quantitative variation which is shown for the skin is best explained by option D. Which shows that fewer people have got skin pigmentation which is lighter than the central peak in the graph, compared to the people who have darker pigmentation than the central peak.

4 0
3 years ago
Read 2 more answers
The mammals whose offspring are little more than embryos are? A. Monotremes B. Marsupials C. Placentals
saveliy_v [14]
The answer is "B. Marsupials". Marsupials undergo relatively premature births compared to many other species, and although this puts the baby at risk, it lessens the risks for the mother.
6 0
3 years ago
Read 2 more answers
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