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crimeas [40]
3 years ago
6

The coordinates of parallelogram UVWZ are U(a, 0), W(c − a, b), and Z(c, 0). Find the coordinates of V without using any new var

iables.
(a, b)


(b, 0)


(c, b)


(0, b)
Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Your welcome! :) Good luck!

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Anastaziya [24]
Shjdkkakskskakshsgsisuelwis code also
6 0
3 years ago
Evaluate (c − b)2 + a2 for a = –5, b = –2, and c = –4.
taurus [48]

(c - b)² + a²


a = -5

b = -2

c = -4


(-4 - (-2))² + (-5)²

(-4 + 2)² + (-5)²

(-2)² + (-5)²

4 + 25

29

3 0
3 years ago
Does anyone know how to do this?? thanks x
Gre4nikov [31]

There's a simple formula for the area of an ellipse:  pi*a*b, where a and b are , half the lengths of the long axis and the short axis respectively.

Here, A = pi*(12 ft)(4 ft) = 48 pi ft^2, or about 150.8 ft^2.

3 0
3 years ago
Multiply. Write your answer in scientific notation. (2 x 10^7) (1 x 10^7)
loris [4]
2 x 10exponent 14 I think
7 0
2 years ago
Simplify and express the result in power notation with positive exponent
Molodets [167]

Answer:

3²

Step-by-step explanation:

Given expression:

\sf (3^{-3} \div 3^{-10}) \times 3^{-5}

Following the <u>order of operations</u>, carry out the calculations inside the parentheses first.

\textsf{Apply the quotient exponent rule} \quad a^b \div a^c=a^{b-c}:

\implies \sf 3^{-3-(-10)} \times 3^{-5}

\implies \sf 3^{-3+10} \times 3^{-5}

\implies \sf 3^{7} \times 3^{-5}

\textsf{Apply the product exponent rule} \quad a^b \times a^c=a^{b+c}:

\sf \implies 3^{7+(-5)}

\sf \implies 3^{7-5}

\sf \implies 3^2

Learn more about exponent rules here:

brainly.com/question/27959936

brainly.com/question/24947526

4 0
1 year ago
Read 2 more answers
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