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Vinil7 [7]
3 years ago
10

Which locations contain carbon?

Chemistry
2 answers:
Aliun [14]3 years ago
5 0

Answer:

all of the answers are correct

Explanation:

<3

Hatshy [7]3 years ago
4 0

Answer:

all the answers are right

Explanation:

i just did it

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What is the pH of a 0.100 M HI solution? Is that neutral, acidic, or basic? acidic What is the pOH of a 0.100 M HI solution? Is
inessss [21]

<u>Answer:</u> The pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.

<u>Explanation:</u>

There are three types of solution: acidic, basic and neutral

To determine the type of solution, we look at the pH values.

  • The pH range of acidic solution is 0 to 6.9
  • The pH range of basic solution is 7.1 to 14
  • The pH of neutral solution is 7.

We are given:

Concentration of HI = 0.100 M

1 mole of HI produces 1 mole of hydrogen ions and 1 mole of iodide ions

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=0.100M

Putting values in above equation, we get:

pH=-\log(0.100)\\\\pH=1

To calculate the pOH of the solution, we use the equation:

pH + pOH = 14

pOH=14-1=13

Hence, the pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.

4 0
3 years ago
How many nucleons are there in an atom with a nuclear charge of +20 and 23 neutrons?
dalvyx [7]

Answer:

43

Explanation:

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2 years ago
X+KOH→CH-CH=CH 2 +KBr+H2O. What is the<br> compound represent “x”?
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3 years ago
A 25.00 mL sample of vinegar was titrated with 39.27 mL of 0.4293 M NaOH. Calculate the concentration of acetic acid in the vine
QveST [7]

Answer:

0.6743 M

Explanation:

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

First we <u>calculate how many NaOH moles reacted</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / volume
  • moles = Molarity * volume
  • 0.4293 M * 39.27 mL = 16.86 mmol NaOH

<em>One NaOH moles reacts with one acetic acid mole</em>, so <u>the vinegar sample contains 16.86 mmoles of acetic acid as well</u>.

Finally we <u>calculate the concentration (molarity) of acetic acid</u>:

  • 16.86 mmol HC₂H₃O₂ / 25.00 mL = 0.6743 M
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3 years ago
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