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Tcecarenko [31]
4 years ago
8

What is the pH of a 0.100 M HI solution? Is that neutral, acidic, or basic? acidic What is the pOH of a 0.100 M HI solution? Is

that neutral, acidic, or basic?
Chemistry
1 answer:
inessss [21]4 years ago
4 0

<u>Answer:</u> The pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.

<u>Explanation:</u>

There are three types of solution: acidic, basic and neutral

To determine the type of solution, we look at the pH values.

  • The pH range of acidic solution is 0 to 6.9
  • The pH range of basic solution is 7.1 to 14
  • The pH of neutral solution is 7.

We are given:

Concentration of HI = 0.100 M

1 mole of HI produces 1 mole of hydrogen ions and 1 mole of iodide ions

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=0.100M

Putting values in above equation, we get:

pH=-\log(0.100)\\\\pH=1

To calculate the pOH of the solution, we use the equation:

pH + pOH = 14

pOH=14-1=13

Hence, the pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.

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pashok25 [27]

When the concentrations of CO2 and H2CO3 are both horizontal lines then the rate of the forward reaction is the same as the rate of the reverse reaction.

<h3>What is rate of reaction?</h3>

The term rate of reaction refers to how fast or slow a reaction proceeds. Recall that the rate  of reaction is measured from the rate of disappearance of reactants or the rate of appearance of products.

When the [CO2] and [H2CO3 ] are both horizontal lines, the rate of the forward reaction is the same as the rate of the reverse reaction.

Let us recall that the reaction is reversible hence addition of H2CO3  will increase the concentration of H2CO3, the reverse reaction would be favored.

Learn more about rate of reaction: brainly.com/question/8592296

4 0
3 years ago
A cube of steel with a mass of 150 grams is heated from 60°C to 150°C.
yan [13]

Answer:

1.

The energy lost by the water is given by:

where

m = 3.0 kg = 3000 g is the mass of water

Cs = 4.179 J/g•°C is the specific heat

is the change in temperature

Substituting,

2.

The energy added to the aluminium is given by:

where

m = 0.30 kg = 300 g is the mass of aluminium

Cs = 0.900 J/g•°C is the specific heat

is the change in temperature

Substituting,

4. 42.9 g

The mass of the water sample is given by

where

is the heat added

is the temperature change

Cs = 4.179 J/g•°C is the specific heat

5. 115.5 J

The heat used to heat the copper is given by:

where

m = 5.0 g is the mass of copper

Cs = 0.385 J/g•°C is the specific heat

is the change in temperature

6. 0.185 J/g•°C

The specific heat of iron is given by:

where

Q = -47 J is the heat released by the iron

m = 10.0 g is the mass of iron

is the change in temperature

Substituting,

Substituting,

Substituting,

Explanation:

8 0
3 years ago
what separation procedure is most likely to happen? .a. freezing a compound will break it down into elements .b. filtering a mix
SOVA2 [1]

Explanation:

i think its B but i'm not fully sure (Correct)

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3 years ago
Predict the empirical formula of these compounds. a. C2N2. b. P4O10. c. N2O5. d. NaCl. e. C9H20. f. B2H6. g. K2Cr2O7. h. Al2Br6.
Stella [2.4K]
The empirical formula is the simplest form of the formula expressed in the lowest ratio. In this case, we just have to divide each subscript by the greatest common factor. Hence.
a. CN
b. P2O5
c.N2O5
d.NaCl
e. C9H20
f. BH3
g.K2Cr2O7
h.AlB3
i.CH
j.SiCl4
5 0
3 years ago
Convert 6.7 x 1024 molecules of nitrogen dioxide into grams.
BlackZzzverrR [31]

Answer:

510 g NO₂

General Formulas and Concepts:

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
  • Reading the Periodic Table
  • Writing Compounds
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

6.7 × 10²⁴ molecules NO₂ (Nitrogen dioxide)

<u>Step 2: Define conversions</u>

Avogadro's Number

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of NO₂ - 14.01 + 2(16.00) = 46.01 g/mol

<u>Step 3: Use Dimensional Analysis</u>

<u />6.7 \cdot 10^{24} \ molecules \ NO_2(\frac{1 \ mol \ NO_2}{6.022 \cdot 10^{23} \ molecules \ NO_2} )(\frac{46.01 \ g \ NO_2}{1 \ mol \ NO_2} ) = 511.901 g NO₂

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules.</em>

511.901 g NO₂ ≈ 510 g NO₂

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3 years ago
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