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inysia [295]
3 years ago
14

Water at 25 °C flows at 5 ft/s through a straight cylindrical tube made of benzoic acid, with a 1-inch inside diameter. If the t

ube is 10 ft long, estimate the mixing-cup average concentration of benzoic acid in the water leaving the tube. The Schmidt number for these conditions is Sc.

Chemistry
1 answer:
defon3 years ago
8 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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Solid sodium reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of hydrogen gas
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57.1g * 6.022*10^23 / 22.9 * 2 = 7.51*10^23 molecules

3 0
3 years ago
Calculate the pH of lemon juice to three significant figures, with a hydrogen ion concentration of
Airida [17]

Answer:

pH = - log [2.12 x 10^-3]

what is the log of 2.22 x 10^-3]

Take the opposite of that,

That is the pH, now, just make certain you use the correct significant figures.

Explanation:

3 0
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The main environmental factors that affect microorganism growth include chemical inhibitors, oxygen, pH, nutrients, moisture and
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The main environmental factors that affect microorganism growth include chemical inhibitors, oxygen, pH, nutrients, moisture and temperature.

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3 0
2 years ago
Describe how the charges of the subatomic particles interact with one another.
DanielleElmas [232]

Answer:

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8 0
3 years ago
Read 2 more answers
A solution is made by dissolving 25.5 grams of glucose (C6H12O6) in 0.325 kilograms of water. If the molal freezing point consta
Bezzdna [24]
1.) Convert grams of glucose to moles of glucose:25.5g gluc. * (1 mol/180g gluc.) = 1.41E-1 mol gluc.      Note. Molar mass gluc. = 180g/mol
2.) Convert grams of solvent to kilograms of solvent:398 g H2O * (1kg H2O/1000g H2O) = 0.398 kg H2O
3.) Determine molality (moles solute/kilogram solvent) of solux:1.41E-1 mol gluc./0.398 kg H2O = 3.5427E-1 mol/kg
4.) Employ Freezing Point Depression equation and determine the freezing point of the solux:
ΔT = i Kf mΔT= ? (°C)Kf = 1.86 (°C kg mol¯1)m = 3.5427E-1 (mol/kg)i = (assumed negligible)
ΔΤ = (1.86)(3.5427E-1)ΔT = 6.589Ε-1°C
5.) ΔT = 6.589Ε-1°C
25.5g gluc. * (1 mol/180g gluc.) = equal 0.14166, not 1.41E-1 mol glucose



7 0
3 years ago
Read 2 more answers
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