Dy/dx (2x⁵ y³ - 4y/x)
dy/dx (2y³ x⁵ - 4y/x)
dy/dx ( 2y³ x⁵ ) - dy/dx (4y/x)
= 2y³ 5x⁴ - (-4y × 1/x²)
=
10x⁶ y³ + 4y
-------------------
x²
To find the number of miles Erma can drive, you will write and equation and solve it to find the amount of miles that can be driven on $600 over the 1600 miles that are allowed.
Daily rate + cost per mile over 1600 = total cost
(65 x 8) + 0.24m = 600
520 + 0.24m = 600
-520 -520
<u>0.24m </u>= <u>80</u>
0.24 0.24
m = 333.33... miles
The maximum number of whole miles she can drive would be 1933 miles (1600 + 333).
3 but in most cases it is 2 real roots and one root has a multiplicity of 2
Answer:
A
Step-by-step explanation:
Answer:
<h3>x^3</h3>
Step-by-step explanation:
We are to find the greatest common factor of x^7, x^3 and x^5
x^7 = x^3 * x^4
x^3 = x^3 * 1
x^5 = x^3 * x^2
From both factors, we cam see that x^3 is common to the three, hence the GCF is x^3
