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3 years ago

-7(a - 3) = 11 - 7a what’s the answer

Mathematics

1 answer:

natali 33 [55]3 years ago

8 0

Answer:

the statement is false there is no solution

Step-by-step explanation:

step 1 -7(a-3)=11-7a

step 2 -7a+21=11-7a

step 3 cancel out the -7a's

step 4 you are left with 21=11 which does not work so it is false

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Can you help with this please and also explain?

stira [4]

Answer:

avocado=4

Step-by-step explanation:

Hi there!

We are given the following equations:

snail + snail - cellphone=avocado

maple leaf * cellphone=10

0+maple leaf=5

snail = cellphone + 1

avocado=?

This may seem confusing at first, but let's try to find the value of one of the items to help us to solve for the others

For example, we have the equation 0 + maple leaf= 5

Which means if we subtract 0 from both sides, we should get the value of the maple leaf

Which means that the maple leaf= 5

Now we know that maple leaf * cellphone = 10

So that means 5*cellphone=10

Divide by 5 on both sides

cellphone= 2

We know that snail = cellphone + 1

As we learned from above, cellphone= 2

Which means that snail = 2+1=3

We know that snail + snail - cellphone = avocado

And as calculated from above, snail = 3 and cellphone = 2

Which means:

3 + 3 - 2= avocado

Add

6-2=avocado

Subtract

4=avocado

Hope this helps!

5 0

3 years ago

The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an

Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = $\dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, w = $\dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}$

Or, w = $\dfrac{-11\pm \sqrt{473}}{2}$

or, w = $\dfrac{-11\pm 21.7}{2}$

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

3 0

3 years ago

44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access

DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.

FileSystemLocked → ∀x Access(x, SystemMailbox)

(c)

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0

3 years ago

What is the coefficient of the x^4 term in the expanded form of (2x-7)^6

Artist 52 [7]

Answer:

The coefficient of $x^{4}$ = 11760