Question

Write an expression for the net change in charge if two electrons are added to each of six atoms in a group. Also, write an expression that represents removing two protons each from a group of six atoms.​

Answer 1

Given:

Two electrons are added to each of six atoms in a group.

To find:

The expression for the net change in charge.

Solution:

Charge of atoms = Number protons - Number of electrons.

Let number of atoms be x.

6 atoms = 2 electrons added

1 atom = $\dfrac{2}{6}$ electrons added

1 atom = $\dfrac{1}{3}$ electrons added

x atoms = $\dfrac{1}{3}x$ electrons added

Therefore, the net change in charge is represented by the expression $-\dfrac{1}{3}x$ because we subtract number of electrons to find atom charge, where, x is the number of atoms.

6 atoms = 2 protons removed

1 atom = $\dfrac{2}{6}$ protons removed

1 atom = $\dfrac{1}{3}$ protons removed

x atoms = $\dfrac{1}{3}x$ protons removed

Therefore, the net change in charge is represented by the expression $-\dfrac{1}{3}x$, where, x is the number of atoms.

Answer 2

Answer:

Adding two electrons to each of six atoms results in a net change in charge of (-2)(6). Removing two protons from each of six atoms results in a net change in charge of (2)(-6).

Step-by-step explanation:

I know this is right because i just did the problem and got it wrong then it showed the correct answer and that is the exact answer so you might wanna switch the answer up a little so you dont get in trouble