Question

Pls help me with this (ill give brainliest)​

Answer 1

Answer:

72.96

Step-by-step explanation:

Let the first circle's radius be r and quarter circle's radius be R

Area of circle = π$r^{2}$

                       = 3.14 × 8 × 8

                       = 200.96 $cm^{2}$

Area of quarter circle = π$R^{2}$/4

                                     = 3.14 × 16 × 16

                                     = 803. 84/4

                                     =200.96

Area of shaded portion = (Area of Quarter circle - Area of semi-circle ACD - Area of triangle ABC) + (Area of the circle -  Area of semi-circle ACD - Area of triangle ABC)

Area of Semi-circle =   Area of the circle divided by 2

                                 = 100.48

Area of triangle = $\frac{bh}{2}$

                           = $\frac{16 * 8}{2}$

                           = 64

Therefore, The area of shaded portion= (200.96-100.48-64) + (200.96 - 100.48 - 64)

= 36.48 +36.48

=72.96