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3 years ago

6/13=3/c what I the answer and show me how you got your answer.show me how you did it.

1 answer:

4 0

6 3
---- * ----
13 c

this is a proportion...so we cross multiply
(6)(c) = (3)(13)
6c = 39...divide both sides by 6
c = 39/6 which reduces to 13/2 or 6 1/2 <== ur answer

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3 years ago

What is the total surface area of the square pyramid below?

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3 years ago

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Of all the weld failures in a certain assembly, 85% of them occur in the weld metal itself, and the remaining 15% occur in the b

Aloiza [94]

Answer:

a.) 0.1028

b.) 0.6477

c.) 0.0388

d.) 3

e.) 2.55

Step-by-step explanation:

Forming a binomial Probability distribution

n = 20

Probability of success for Weld metal failure = 85%

Probability of success for base metal failure = 15%

We use the probabilit distribution formula of combination to solve the problem.

P(x=r) = nCr * p^r * q^n-r

a.) if exactly 5 are base metal failures, then p = 15 and our solution becomes:

P(x=5) = 20C5 * 0.15^5 * 0.85^15

P(x=5) = 0.1028

b.) probability that fewer than 4 are base metal failure= P(x=0) + P(x=1) + P(x=2) + P(x=3)

P(x=0) = 20C0 * 0.15^0 * 0.85^20 = 0.0388

P(x=1) = 20C1 * 0.15¹ * 0.85^19 = 0.1368

P(x=2) = 20C2 * 0.15² * 0.85^18 = 0.2293

P(x=3) = 20C3 * 0.15³ * 0.85^17 = 0.2428

Probability that fewer than 4 are base metal failures becomes: 0.038 + 0.1368 + 0.2293 + 0.2428 = 0.6477

c.) probability that none of them are results of base metal failure = P(x=0). As earlier calculated,

P(x=0) = 0.0388

d.) mean of base metal failures = np = 20*0.15 = 3

e.) standard deviation of base metal failures = √np(1-p)

=3 * (1 - 0.15) = 3 * 0.85

= 2.55

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3 years ago

Adam has 3 coins in his pocket and they are all different from each other. Ben has 3 coins in his pocket and they are all the sa

Elenna [48]

Answer:

The possible coins are:

P = penny = $0.01

N = nickel = $0.05

D = dime = $0.10

Q = quarter = $0.25

H = half dollar = $0.50

We know that Adam has 3 coins in his pocket, and all of them are different, then the money that Adam has can be represented with (A + B + C)

Behn has 3 coins, and all of them are the same, then if his coin has a value X, he has a total of 3*X

We know that Adam has half as much money as Ben, this can be written as:

(A + B + C) = 3*X/2

The easier way to solve this, is to play with different values of X, and see if we can find the values of A, B and C.

For example, if X = $0.10

then:

(A + B + C) = $0.10*(3/2) = $0.15

We can find 3 different value of coins for this equation? No, we cant, so X = $0.10 is also discarded.

if x = $0.50 then:

(A + B + C) = (3/2)*$0.50 = $0.75

Here we could have:

A = $0.50

B = $0.25

then: A + B = $0.75

But we still have the coin C.

If we take X = $0.25 then:

(A + B + C) = (3/2)*$0.25 = $0.375

We could round the right part to $0.40

then the coins in the left part would be:

A = $0.25

B = $0.10

C = $0.05

A + B + C = $0.25 + $0.10 + $0.05 = $0.40

This is a strech, but is the only thing we can make with the given problem.

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3 years ago

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pav-90 [236]

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