3 years ago

75

Mathematics

1 answer:

Vinvika [58]3 years ago

8 0

Answer:

B. 210°

hope it helps

have a nice day

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Given the equation:

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Let's determine the identity:

Apply the trigonometric identity:

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Thus, we have:

$\begin{gathered} \frac{\sin^2x+\cos^2x}{\frac{1}{\sec x}} \\ \\ =(\sin ^2x+\cos ^2x)(\sec x) \\ \text{Where:} \\ (\sin ^2x+\cos ^2x)=1 \\ \\ We\text{ have:} \\ (\sin ^2x+\cos ^2x)(\sec x)=1\sec x=\sec x \end{gathered}$

The equation is an identity.

Therefore, the trignonometric identity you would use to verify the equation is:

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ANSWER:

$\cos ^2x+\sin ^2x=1$

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