Answer:
x1, x2 = 4.74 , -2.74
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 2x - 13
a = 1 b = -2 c = -13
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1
x1 = (2 + √ (4 + 52)) / 2
x1 = (2 + √ 56 ) / 2
x1 = (2 + 7.48) / 2
x1 = 9.48 / 2
x1 = 4.74
x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1
x2 = (2 - √ (4 + 52)) / 2
x2 = (2 - √ 56 ) / 2
x2 = (2 - 7.48) / 2
x2 = -5.48 / 2
x2 = -2.74
Answer:
The answer to your question is x = 17.32; y = 8.67
Step-by-step explanation:
Process
1.- Use trigonometric functions to find x and y
a) sin Ф =
Ф = 60°
opposite side = 15
hypotenuse = ?
hypotenuse = 17.32
b) cosФ =
y = 8.67
23 x 10,000 = 230,000
Another name for 23 ten thousand is: Two hundred thirty thousand
And another name also is: 230 Thousands
The algebraic expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)
<em><u>Solution:</u></em>
Given the statement:
Three sets of a sum of a number and four are added to the sum of seven times the same number and thirteen
Let us first understand the given statement,
Let the number be "x"
" sum of a number and four" means x + 4
"Three sets of a sum of a number and four" translated to 3(x + 4)
"sum of seven times the same number and thirteen" means 7x + 13
<em><u>Thus the algebraic expression for given statement is:</u></em>
<em><u>Using distributive property in above expression</u></em>
Therefore,
<em><u>Combine the like terms</u></em>
Thus the required expression for given statement is: 10x + 25 or 3(x + 4) + (7x + 13)