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bogdanovich [222]
4 years ago
7

One gram of protein contains 4 calories. One gram of fat contains 9 calories. A snack has 60 calories from p grams of protein an

d f grams of fat. The equation 4p + 9f = 60 represents the relationship between these quantities. If there are 6 grams of fat in the snack, how many grams of protein are there? Show your reasoning.
Mathematics
1 answer:
nikitadnepr [17]4 years ago
4 0

Answer:

1.5 grams of protein.

Step-by-step explanation:

The equation that represents the relationship between protein and fat is as follows :

4p + 9f = 60 ....(1)

We need to find the grams of protein are there if there are 6 grams of fat in the snack.

Put f = 6 in the above equation (1).

4p + 9(6)= 60

4p + 54 = 60

Subtract 54 to the both sides,

4p + 54-54 = 60-54

4p = 6

⇒ p = 1.5 grams

It means the snack contains 1.5 grams of protein.

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Daniel brother can eat 4 ice cream sandwiches every 30 minutes his brother can eat double that how many ice cream sandwiches wil
Snowcat [4.5K]

Answer:

3 minutes and 45 seconds

Step-by-step explanation:

His brother can eat 1 ice cream sandwich every 3 minutes and 45 seconds I found this out by dividing 30 by 8 then I got 3.75 then I converted .75 to 75% of 60 was 45 thus ending up with 3:45

8 0
4 years ago
What is the largest perfect square factor of √125.
kykrilka [37]

Answer:

25

Just list all the factors of anything that multiplies to 125 and the largest perfect square factor is 25 and that is a perfect square root (5 x 5).

6 0
3 years ago
I just want the equation you don't have to solve.
AlexFokin [52]

The equation to solve this should be x+3x=60

4 0
4 years ago
A townhouse in San Francisco was purchased for $80,000 in 1975. The appreciation of the building is modeled by the equation: A=8
jonny [76]

Answer:

In 1981 was the building worth double it’s value.

Step-by-step explanation:

Given : A townhouse in San Francisco was purchased for $80,000 in 1975. The appreciation of the building is modeled by the equation : A=80000(1.12)^t, where t represents time in years.

To find : In what year was the building worth double it’s value in 1975?

Solution :

The amount is $80,000.

The building worth double it’s value in 1975.

i.e. amount became A=2(80000).

Substitute in the model,

2(80000)=80000(1.12)^t

(1.12)^t=\frac{2(80000)}{80000}

(1.12)^t=2

Taking log both side,

t\log (1.12)=\log 2

t=\frac{\log 2}{\log (1.12)}

t=6.11

i.e. Approx in 6 years.

So, 1975+6=1981

Therefore, in 1981 was the building worth double it’s value.

4 0
4 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
3 years ago
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