All categories

4 years ago

To simplify 48 ÷ 6 • 3, which operation should be performed first?

2 answers:

7 0

When in doubt use BODMAS

Brackets of Division Multiplication Addition and Subtraction.

☆Division first, then multiplication
1st) 48 ÷6 = 8

2nd) 8 × 3 = 24

Answer is 24

dangina [55]4 years ago

4 0

Multiplication. If you need help just remember PEMDAS.

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

You might be interested in

2.The number of tickets sold to a play for each showing is 78, 84, 87, 80, 91, 95, and 80.

Luden [163]

Answer:

$Min =78$

The maximum is :

$Max = 95$

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

$Median =84$

Now we can find the quartile 1 we analyze the first 4 values 78, 80,80, 84 and the first quartile would be:

$Q_1= \frac{80+80}{2}= 80$

Now we can find the quartile 3 we analyze the last 4 values 84,87, 91, 95 and the third quartile would be:

$Q_3= \frac{87+91}{2}=89$

And finally the 5 number summary would be:

$Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96$

Step-by-step explanation:

We have the following data given:

78, 84, 87, 80, 91, 95, and 80.

The first step is order the dataset on increasing way and we got:

78, 80,80, 84,87, 91, 95

We can begin finding the minimum value and for this case is:

$Min =78$

The maximum is :

$Max = 95$

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

$Median =84$

Now we can find the quartile 1 we analyze the first 4 values 78, 80,80, 84 and the first quartile would be:

$Q_1= \frac{80+80}{2}= 80$

Now we can find the quartile 3 we analyze the last 4 values 84,87, 91, 95 and the third quartile would be:

$Q_3= \frac{87+91}{2}=89$

And finally the 5 number summary would be:

$Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96$

5 0

4 years ago

The value of 26 – 16 divided by 2+3•4 is 30 32 06 22 PLEASE HELP!!!!!!

viva [34]

Answer:

30.

Step-by-step explanation:

3 0

3 years ago

Please answer correctly !!!!!!! Will mark Brianliest !!!!!!!!!!!

icang [17]

Answer:

$x=-2\\x=2$

(You only need to give one solution)

Step-by-step explanation:

We have the following equation

$(x^2+1)^2-5x^2-5=0$

First, we need to foil out the parenthesis

$x^4+2x^2+1-5x^2-5=0$

Now we can combine the like terms

$x^4-3x^2-4=0$

Now, we need to factor this equation.

To factor this, we need to find a set of numbers that add together to get -3 and multiply to give us -4.

The pair of numbers that would do this would be 1 and -4.

This means that our factored form would be

$(x^2-4)(x^2+1)=0$

As the first binomial is a difference of squares, it can be factored futher into

$(x^2+1)(x+2)(x-2)=0$

Now, we can get our solutions.

The first binomial will produce two complex (Not real) solutions.

$x+2=0\\\\x=-2$

$x-2=0\\\\x=2$

So our solutions to this equation are

$x=-2\\x=2$

3 0

3 years ago

Rule that maps each preimage

Yuri [45]

The answer to this question would be
5= rotating 90° clockwise
6= mirrored diagonally (\)

In this case, the picture in number 5 is moved 1 quadrant to the clockwise direction. In this problem, it is either the picture rotated 90° clockwise or mirrored to the Y lines. If it mirrored, the effect would be X point become minus. But seeing the point B and C, the effect is
1. X and Y switched
2. X become minus
This effect is gained when you rotating 90° clockwise

In number 6, the picture moved 2 quadrants. It will be either rotated 180° or mirrored diagonally. The effect on the image is:
1. X and Y switched
2. Both X and Y become minus
This effect is gained if the shape was mirrored.

5 0

3 years ago

3. The following are the scores you shot in five rounds of golf: 70,80,75,75,80. The variance is: A. 3.74 C. 14 B. 196 D. 70

Paladinen [302]

Answer:

Option C.

Step-by-step explanation:

For a given set of N elements:

{x₁, x₂, ..., xₙ}

The mean is given by:

$M = \frac{x_1 + x_2 + ... + x_n}{N}$