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3 years ago

Can someone explain to me how to do this exercise?

1 answer:

4 0

Hi
You should put into them.I mean
1-This is 2 part.First, you should put f(-1) then you should put what you found.
Solve is:f(-1)=3(-1)-2(-1)^2 so -3-2=-5 then put in other one:if f(-5):-15-50=-65
Is it correct?

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Write an equation of each line with the given slope and y-intercept. slope =1/2 ; y-intercept = 0

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Answer:

y=1/2x

Step-by-step explanation:

Equations of lines are written in slope-intercept form:

y=mx+b

where m is the slope and b is the y intercept.

The slope is 1/2 and the y-intercept is 0. Therefore, we can substitute 1/2 for m and 0 for b.

y=1/2x+0

Adding 0 onto the end doesn't change the equation and doesn't serve a purpose, so it can be removed from the end of the equation.

y=1/2x

The equation is: y=1/2x

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4 years ago

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3 years ago

Simplify [0.009÷0.004]-1/2

pantera1 [17]

Answer:

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4 years ago

Which of the following best describes a line

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I would answer, but you didn't give any options.

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3 years ago

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A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

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Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

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4 years ago