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3 years ago

Pls help for this question! no wrong answers pls

Mathematics

1 answer:

ankoles [38]3 years ago

8 0

Answer:

41.29 cm²

Step-by-step explanation:

From the question,

Area of the shaded portion = Area of the circle - area of the square.

A' = πr²-L²...… Equation 1

Where A' = Area of the shade portion, r = radius of the circle, L = length of the square, π = pie

Given: r = 4 cm, L = 3 cm

Constant: π = 22/7.

Substitute these values into equation 1

A' = [(22/7)×4²]-3²

A' = 50.29-9

A' = 41.29 cm²

Hence the area of the shaded portion is 41.29 cm²

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ivanzaharov [21]

Answer:

Since 4 is the largest number its the hypotenuse. The two 3s are equal so they are interchangeable so it doesn't matter where you put them. If its a right triangle the hypotenuse is opposite the right angle.

Step-by-step explanation:

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3 years ago

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Radda [10]

Answer:

C. x > 15

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3 years ago

Read 2 more answers

George placed the numbers -1/2 , 8/9 , 0.2 and on the numberline . Which of the numbers is furthest from zero ?

dimaraw [331]

Furthest from 0, so I am going to take the absolute value of these numbers. The absolute value will tell us how far away from 0 these numbers are.
|-1/2| = |- 0.5| = 0.5
|8/9| = |0.88| = 0.88
|0.2| = 0.2

so the number furthest from 0 is 8/9

7 0

3 years ago

The explicit rule for the arithmetic sequence shown in the graph is a↓n=9.5+2(n-1)

Virty [35]

Answer:

True.

Step-by-step explanation:

The explicit form for an arithmetic sequence is:

$a_n=a_1+d(n-1)$

where $a_1$ is the first term and $d$ is the common difference.

The common difference here is 2 because the y's are going up by 2 while the x's are going up by 1.

Yes, the common difference is the slope.

So we have d=2.

The first term is 9.5 because that is what happens when x=1.

x is n.

y is $a_n$ .

So the answer is true.

----

You can also verify by plugging in numbers for n and see if you get the outputs mentioned in the pairs given:

Let n=1:

$a_1=9.5+2(1-1)$

$a_1=9.5+2(0)$

$a_1=9.5+0$

$a_1=9.5$

Let n=2:

$a_2=9.5+2(2-1)$

$a_2=9.5+2(1)$

$a_2=9.5+2$

$a_2=11.5$

Let n=3:

$a_3=9.5+2(3-1)$

$a_3=9.5+2(2)$

$a_3=9.5+4$

$a_3=13.5$

Let n=4:

$a_4=9.5+2(4-1)$

$a_4=9.5+2(3)$

$a_4=9.5+6$

$a_4=15.5$

Let n=5:

$a_5=9.5+2(5-1)$

$a_5=9.5+2(4)$

$a_5=9.5+8$

$a_5=17.5$

Let n=6:

$a_6=9.5+2(6-1)$

$a_6=9.5+2(5)$

$a_6=9.5+10$

$a_6=19.5$

We have confirmed that we get all 6 of the mentioned points using the equation they gave.

5 0

3 years ago

Please help radical expression dividing

77julia77 [94]

$\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
\begin{cases}
63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}$

$\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
\\\\\\
\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}$

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.

6 0

3 years ago