Question

Which function has a range of y<3? y=3(2) y=2(3) O y=-(2)* +3 O y= (2)* - 3

Answer 1

option C is correct.

Step-by-step explanation:

If a function is defined as

$f(x)=a^x$ where, a>0, then the range of the function is greater than 0.

$a^x>0$               .... (1)

Option A: Using inequity (1),

$2^x>0$

Multiply both side by 3.

$3(2^x)>0$

The range of first function is y>0. Therefore option A is incorrect.

Option B: Using inequity (1),

$3^x>0$

Multiply both side by 2.

$2(3^x)>0$

The range of second function is y>0. Therefore option B is incorrect.

Option C: Using inequity (1),

$2^x>0$

Multiply both side by -1.

$-2^x$

Add 3 on both the sides.

$-2^x+3$

$y$

The range of first function is y<3. Therefore option C is correct.

Option D: Using inequity (1),

$2^x>0$

Subtract 3 from both the sides.

$2^x-3>-3$

$y>-3$

The range of second function is y>-3. Therefore option D is incorrect.