Significant figures are all the digits excluding leading zeros for small decimals and zeros at the end of an integer.
45.030 has 5 significant figures because the zero at the end is after the decimal point. This means that the number was measured with 3 decimal places of precision. If the last zero was not significant, the number would be written 45.03.
On the other hand, 45030 only has 4 significant figures. Hope this helps!
•3.9g of ammonia
•molar mass of ammonia = 17.03g/mol
1st you have to covert grams to moles by dividing the mass of ammonia with the molar mass:
(3.9 g)/ (17.03g/mol) = 0.22900763mols
Then convert the moles to molecules by multiplying it with Avogadro’s number:
Avogadro’s number: 6.022 x 10^23
0.22900763mols x (6.022 x 10^23 molecs/mol)
= 1.38 x 10^23 molecules
A radioactive half-life talks about the amount of time
it takes for half of the original isotope to deteriorate.
The solution for this problem is:
Half-life (lst order
reaction) = ln2 over k <span>
<span>so half-life = .693 over 3.25 = .213 day is the
half-life for the metabolism reaction</span></span>
<span> </span>
Answer:
3.9
Explanation:
Let's consider the following reaction at equilibrium.
CO(g) + Cl₂(g) ↔ COCl₂(g)
We can find the pressures at equilibrium using an ICE chart.
CO(g) + Cl₂(g) ↔ COCl₂(g)
I 0.96 1.15 0
C -x -x +x
E 0.96-x 1.15-x x
The sum of the partial pressures is equal to the total pressure.
pCO + pCl₂ + pCOCl₂ = 1.47
(0.96-x) + (1.15-x) + x = 1.47
2.11 - x = 1.47
x = 0.64
The pressures at equilibrium are:
pCO = 0.96 - x = 0.32 atm
pCl₂ = 1.15 - x = 0.51 atm
pCOCl₂ = x = 0.64 atm
The pressure equilibrium constant (Kp) is:
Kp = pCOCl₂ / pCO × pCl₂
Kp = 0.64 / 0.32 × 0.51
Kp = 3.9