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kati45 [8]
2 years ago
11

If 100mL was diluted of a 2.0 M solution of sodium chloride by adding an additional 100 mL of water, what would the new molarity

be?
Chemistry
1 answer:
andrew-mc [135]2 years ago
7 0
I need help with my questions sorry
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8. Which type of bond results when one or more valence
Gekata [30.6K]

Answer:

B

Explanation:

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3 years ago
Is there more or less air near sea level
vampirchik [111]

there is more air near sea level

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2 years ago
Explain how to convert a mass of compound A to a mass of compound D in words with no equations using the following reaction 2A +
leonid [27]

Answer:

Explanation:

The given reaction equation is:

                2A + 4B → C + 3D

We know the mass of compound A in the reaction above. We are to find the mass of compound D.

We simply work from the known mass to calculate the mass of the unkown compound D

Using the mole concept, we can find the unknown mass.

Procedures

  • We first find the molar mass of the compound A from the atomic units of the constituent elements.
  • We then use the molar mass of A to calculate its number of moles using the expression below:  

            Number of moles of A = \frac{mass of A}{molar mass of A}

  • Using the known number of moles of A, we can work out the number of moles of D.

           From the balanced equation of the reaction, it is shown that:

         2 moles of compound A was used up to produced 3 moles of D

  Then \frac{3}{2} x number of moles of A would give the number of moles of D

  • Now that we know the number of moles of D, we can find its mass using the expression below:

             Mass of D = number of moles of D x molar mass of D

8 0
2 years ago
Which element is presented in all organic compounds
DerKrebs [107]
Carbon and hydrogen
3 0
3 years ago
Please help me
Wittaler [7]

Answer:

pH = 6.999

The solution is acidic.

Explanation:

HBr is a strong acid, a very strong one.

In water, this acid is totally dissociated.

HBr + H₂O  →  H₃O⁺  +  Br⁻

We can think pH, as - log 7.75×10⁻¹² but this is 11.1

acid pH can't never be higher than 7.

We apply the charge balance:

[H⁺] = [Br⁻] + [OH⁻]

All the protons come from the bromide and the OH⁻ that come from water.

We can also think [OH⁻] = Kw / [H⁺] so:

[H⁺] = [Br⁻] + Kw / [H⁺]

Now, our unknown is [H⁺]

[H⁺] =  7.75×10⁻¹² + 1×10⁻¹⁴ / [H⁺]

[H⁺] = (7.75×10⁻¹² [H⁺] + 1×10⁻¹⁴) /  [H⁺]

This is quadratic equation:  [H⁺]² - 7.75×10⁻¹² [H⁺] - 1×10⁻¹⁴

a = 1 ; b = - 7.75×10⁻¹² ; c = -1×10⁻¹⁴

(-b +- √(b² - 4ac) / (2a)

[H⁺] = 1.000038751×10⁻⁷

- log [H⁺] = pH → 6.999

A very strong acid as HBr, in this case, it is so diluted that its pH is almost neutral.

8 0
3 years ago
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