The answer is C
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Answer:
Mass, m = 141.96 kg
Explanation:
Given that,
Moles = 5.07
Molar mass of N₂ = 28 g/mol
We need to find the mass of 5.07 mol N₂.
We know that,
No of moles is equal to mass divided by molar mass i.e.
Where
m is mass of 5.07 mol of N₂
So,
So, the required mass of 5.07 mol N₂ is 141.96 kg.
The given question is incomplete. The complete question is:
In the chemical reaction: , with 8 grams of and 16 grams of and the reaction goes to completion, what is the excess reactant and how much of that would remain?
A) 6 grams of
B) 7 grams of
C) 8 grams of
D) 12 grams of
E) 14 grams of
Answer: A) 6 grams of
Explanation:
To calculate the moles :
According to stoichiometry :
1 moles of require 2 moles of
Thus 0.5 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
(4.0-1.0) = 3.0 moles of are left unreacted
Mass of remained=
Thus 6.0 g of will remain.