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3 years ago

To solve the inequality -4x < 8, you would divide both sides of the inequality by -4. true or false

1 answer:

6 0

True
but, you can also add 4x to both sides then mius 8 from both sides then divide both sides by 4 as well

true is the answer (if this is a trick to see if I remember to flip the sign, then you also have to flip the sign when dividing by a negiatve number, don't forget)

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3 years ago

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A woman walks due west on the deck of a ship at 3 mi/h. The ship is moving north at a speed of 22 mi/h. Find the speed and direc

Minchanka [31]

Answer: The speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.

Step-by-step explanation:

Since we have given that

Speed at which woman walks due west = 3 mi/hr

Speed at which ship moving due north = 22 mi/hr

Now it forms "Pythagorus theorem":

So, it becomes,

$H^2=B^2+P^2\\\\H^2=3^2+22^2\\\\H^2=9+484\\\\H^2=493\\\\H=\sqrt{493}\\H=22.20\ mi/hr$

And the direction of the woman relative to the surface of the water is given by

$\theta=\sin^{-1}x(\dfrac{3}{22.2})=7.76\approx 8^\circ$

Hence, the speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.

5 0

3 years ago

20 points!!!

OverLord2011 [107]

Answer: y+3 = 4( x + 1)

Step-by-step explanation:

The equation in point slope form is given as :

y - $y_{1}$ = m ( x - $x_{1}$ ) , where m is the slope

slope = 4

point given : (-1,-3)

Using the formula :

y - $y_{1}$ = m ( x - $x_{1}$ )

and substituting the value , we have

y - (-3) = 4 (x -{-1} )

y+3 = 4( x + 1)

8 0

3 years ago

Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a

Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-620=\dfrac{749-620}{70-30}(x-30)$

$y-620=\dfrac{129}{40}(x-30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}$

Adding 620 on both sides, we get

$y=\dfrac{129}{40}x-\dfrac{387}{4}+620$

$y=\dfrac{129}{40}x+\dfrac{2480-387}{4}$

$y=\dfrac{129}{40}x+\dfrac{2093}{4}$

We need to find the y-value for $x=57$ .

$y=\dfrac{129}{40}(57)+\dfrac{2093}{4}$

$y=183.825+523.25$

$y=707.075$

$y\approx 707.1$

Therefore, the required linear equation for the given situation is $y=\dfrac{129}{40}x+\dfrac{2093}{4}$ and the average score for persons taking a 57-hour review course is 707.1.

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2 years ago