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ladessa [460]
3 years ago
9

PLEASE HELP WILL GIVE 20 POINTS!!!

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer:

a

Step-by-step explanation:

you divide three from both sides and get m-3 = -2. then you add 3 to both sides and get m=1

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A lot, 1:6 + 3:4 +3 = .116789465 hope this helps....
7 0
3 years ago
Find the greatest common factor of 9 and 14
Ratling [72]

The biggest common factor number is the GCF number. So the greatest common factor 9 and 14 is 1.


5 0
2 years ago
Read 2 more answers
AWARDING EXTRA POINTSWhat is the distance between point A (-3, -2) and Point B (4, -7)?
kenny6666 [7]

Answer:

Hi there!

Your answer is:

<em>8</em><em>.</em><em>6</em><em> </em><em>units</em>

Step-by-step explanation:

The distance formula is

√ ( (x2-x1)^2 + (y2-y1)^2 )

In your points:

A (-3, -2)

-3 is x1

-2 is y1

B (4, -7)

4 is x2

-7 is y2

Plug in to distance formula

√ ( 4-( -3))^2 + ( -7 - (-2))^2

√ (4+3)^2 + (-7+2)^2

√ (7^2) + ( -5)^2

√ 49 + 25

√ 74

This equals roughly 8.6 units!

4 0
3 years ago
Line segment ST is dilated to create line segment S'T' using the dilation rule DQ,2. 25. Point Q is the center of dilation. Line
abruzzese [7]

The distance between points S' and S is x= 2.5 units.

<h2>Given that</h2>

Line segment ST is dilated to create line segment S'T' using the dilation rule DQ 2. 25.

Point Q is the center of dilation.

Line segment ST is dilated to create line segment S prime T prime.

The length of QT is 1. 2 and the length of QS is 2.

The length of SS prime is x and the length of TT prime is 1. 5.

<h3>We have to determine</h3>

What is x, the distance between points S' and S?

<h3>According to the question</h3>

Line segment ST is dilated to create line segment S'T' using the dilation rule DQ, 2.25.

Also, SQ = 2 units, TQ = 1.2 units, TT'=1.5, SS' = x.

Since the line ST is dilated to S'T' with the center of dilation Q, the triangles STQ and S'T'Q must be similar.

We know that the corresponding sides of two similar triangles are proportional.

So, from ΔSTQ and ΔS'T'Q.

\dfrac{SQ}{S'Q} = \dfrac{TQ}{T'Q}\\&#10;\\&#10;\dfrac{SQ}{SQ+SS} = \dfrac{TQ}{TQ+TT'}\\&#10;\\ &#10;\dfrac{2}{2+x} = \dfrac{1.2}{1.2+1.5}\\\rm &#10;\\&#10;\dfrac{2}{2+x} = \dfrac{1.2}{2.7}\\\\ \dfrac{2}{2+x} = \dfrac{12}{27}\\\\2(27) = (2+x) 12\\\\ 54 = 24 + 12x\\&#10;\\&#10;12x = 54-24\\&#10;\\&#10;12x=30\\&#10;\\&#10;x = \dfrac{30}{12}\\&#10;\\&#10;x = 2.5

Hence, the distance between points S' and S is x= 2.5 units.

To know more about Pythagoras Theorem click the link given below.

brainly.com/question/16016926

5 0
2 years ago
How do I subtract 6.45 from 81.3
Aleks [24]
Simple just subtract and u get-74.85
5 0
2 years ago
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