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BigorU [14]
3 years ago
14

Solve this equation 90x-60y is equal to 68 and 90x-70y is equal to 91​

Mathematics
2 answers:
uranmaximum [27]3 years ago
5 0
X=-7/9


Thanks so much
Tanzania [10]3 years ago
3 0

Answer:

Step-by-step explanation:

90x - 60y = 68.....multiply by -1

90x - 70y = 91

---------------------------

-90x + 60y = -68 (result of multiplying by -1)

90x - 70y = 91

---------------------------add

-10y = 23

y = -23/10 <===

90x - 60y = 68

90x - 60(-23/10) = 68

90x + 138 = 68

90x = 68 - 138

90x = - 70

x = -70/90

x = -7/9 <=====

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Answer/Step-by-step explanation:

1. The figure is composed of a triangle and a rectangle.

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base = 4 ft

height = 12 - 8 = 4ft

Area of triangle = ½*4*4 = 8 ft²

Area of rectangle = length * width

Length = 8 ft

Width = 4 ft

Area of rectangle = 8*4 = 32 ft²

✔️Area of the figure = 8 + 32 = 40 ft²

2. The figure is composed of a semicircle and a triangle

Area of the semicircle = ½(πr²)

radius (r) = 3 cm

π = 3

Area = ½(3*3²) = 13.5 cm²

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base = 3*2 = 6 cm

height = 6 cm

Area = ½*6*6 = 6 cm²

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2 years ago
There are 305 days in a year how many days in 3 years
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Answer:

Step-by-step explanation:

8 0
3 years ago
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(Multi Step Algebra)<br>15x+12=19x-24<br>what is the answer? help me please ​
solmaris [256]

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Step-by-step explanation:

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The length of a 1-inch paperclip is about 1.6 x 10−5 miles. It takes about 1.5 x 1010 paperclips linked together to reach the mo
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Answer:

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Step-by-step explanation:

Length of 1-inch paperclip = 1.6\times 10^{-5} miles

Number of paperclips used to reach the moon = 1.5 × 10¹⁰

Total distance from the moon = Number of paper clips used × Length of one clip

= (1.5 × 10¹⁰) × (1.6 × 10⁻5)

= (1.5 × 1.6) (10¹⁰× 10⁻⁵)

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3 years ago
Suppose that the demand Q^Dand supply Q^Sfor maize meal in Kimberley is given by p=120-0.7Q^Dand p=3+0.2Q^S where the quantity i
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Answer:

  20 rands/kg

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Step-by-step explanation:

The equilibrium quantity and price are the solution to the system of equations ...

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Setting these equal, we get ...

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The equilibrium price of maize meal is 29 rands per kg; the market equilibrium quantity is 130,000 kg.

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