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Helga [31]
3 years ago
12

There will be 6 people at ellies pie party she wants to bake enough pie so each person can eat at least 1/5 of pie what is the m

inimum number of pies ellie should bake?
Mathematics
1 answer:
tatyana61 [14]3 years ago
8 0

Answer:

2

Step-by-step explanation:

She needs to have 6 portions of 1/5 pie size.

6 portions of 1/5 pie size is 6/5 of a pie.

6/5 of a pie is the same as 1 1/5 (one and one-fifth) pies.

Since she only bakes full pies, she must round up to the next higher whole number, so she must bake 2 pies.

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Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneou
Anna35 [415]
For this case we have the following equation:
 3 \sqrt{x+6}=-12
 Rewriting we have:
 \sqrt{x+6}= \frac{-12}{3}
 \sqrt{x+6}=-4
 We raise both members of the equation to the square:
 (\sqrt{x+6})^2=(-4)^2
 Rewriting we have:
 x+6=16
 x=16-6
 x=10
 It's a extraneous solution because equality is not met by substituting x = 10 in the original equation:
 3 \sqrt{10+6}=-12
 3 \sqrt{16}=-12
 3(4)=-12
 12=-12
 Answer:
 
The solution is:
 
x=10
 It's a extraneous solution

6 0
3 years ago
Help PLEASE (look at picture)
elena-14-01-66 [18.8K]

Answer:

16

Step-by-step explanation:

So for QR is 1-(-3)=4

QT:|-2-2|=4

TS: |-2-(-2)|=4

RS: 2-(-2)=4

and they plus together is 4x

4x4 = 16

I hope this helps, have a blessed day. :D

6 0
1 year ago
Oct 09, 11:40:51 AM
kumpel [21]
Get it sis 57
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8 0
3 years ago
A rectangle has a perimeter of 84 miles and a height of 26 miles .what is the length of the base?
ExtremeBDS [4]

Answer:

16 miles

Step-by-step explanation:

The height is 26 miles. Multiply that by 2 which gets 52 and then subtract that from 84. That gives you 32 which means the sum of the lengths is 32/2 which is 16 miles

6 0
3 years ago
PLEASE NEEED HEELPP
krok68 [10]
There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area. 
only A and E satisfy both inequality, in the overlapping shaded area.

 
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true. 
 for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities. 
Do the same for point E (5,-4)

Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area. 
8 0
2 years ago
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