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Debora [2.8K]
4 years ago
12

Translate this sentence into an inequality: A cheetah can reach a speed of 70 mph. However, this speed can be maintained for no

more than 1,640 feet.
A. d ≤ 1,640
B. d ≥ 1,640
C. d > 1,640
D. d < 1,640
Mathematics
1 answer:
bezimeni [28]4 years ago
4 0

The sentence says the speed can be maintained for no more than 1640 feet.

The "no more" means 1640 feet or less ,so the equation would be d is less than or equal to 1640.

The correct equation is A.

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Find the missing lengths of the sides.
Anarel [89]

Given:

The figure of a right angle triangle.

a=b

Hypotenuse = 9\sqrt{2} in.

To find:

The missing lengths of the sides.

Solution:

In the given right angle triangle both legs a and b are equal, and hypotenuse is 9\sqrt{2} in.

Using Pythagoras theorem, we get

Hyponteuse^2=Base^2+Perpendicular^2

(9\sqrt{2})^2=(a)^2+(b)^2

81(2)=(a)^2+(a)^2                    [\because a=b]

81(2)=2(a)^2

Divide both sides by 2.

81=(a)^2

Taking square root on both sides.

\pm \sqrt{81}=a

\pm 9=a

Side cannot be negative. So,

9=a

Thus, the missing side lengths are a=9 in and b=9 in.

Therefore, the correct option is C.

6 0
3 years ago
Find the length of the missing side. triangle with an 8 inch side and 12 inch side with a right angle 8.9 in. 104 in. 4 in 14.4
Mamont248 [21]

Given:

In a triangle, length of one side is 8 inches and length of another side is 12 inches, and an angle is a right angle.

To find:

The length of the missing side.

Solution:

In a right angle triangle,

Hypotenuse^2=Perpendicular^2+Base^2

Suppose the measures of sides adjacent to the right angle are 8 inches and 12 inches.  

Substituting Perpendicular = 8 inches and Base = 12 inches, we get

Hypotenuse^2=8^2+12^2

Hypotenuse^2=64+144

Hypotenuse^2=208

Taking square root on both sides, we get

Hypotenuse=\sqrt{208}

Hypotenuse=14.422205

Hypotenuse\approx 14.4

The length of the missing side is 14.4 inches. Therefore, the correct option is D.

4 0
3 years ago
For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th
alexira [117]

Answer:

The inner function is h(x)=4x^2 + 8 and the outer function is g(x)=3x^5.

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

Step-by-step explanation:

A composite function can be written as g(h(x)), where h and g are basic functions.

For the function f(x)=3(4x^2+8)^5.

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have 4x^2+8 inside parentheses. So h(x)=4x^2 + 8 is the inner function and the outer function is g(x)=3x^5.

The chain rule says:

\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)

It tells us how to differentiate composite functions.

The function f(x)=3(4x^2+8)^5 is the composition, g(h(x)), of

     outside function: g(x)=3x^5

     inside function: h(x)=4x^2 + 8

The derivative of this is computed as

\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

3 0
4 years ago
9. Five times a number is the same as the number added to five. What is the<br> number?
Alenkinab [10]
Let x be the number

5x = x + 5

subtract x from both sides

5x - x = 5

4x = 5

Divide both sides by 4

4x/4 = 5/4

x = 5/4

=======

Check:

5 * (5/4) = (5/4) + 5

25/4 = 1.25 + 5

6.25 = 6.25





Hope it helps . Note that I am a sixth grade student and I don’t know anything . I got help from somebody
4 0
3 years ago
Help anyone<br> 8th grade math need it asap
andre [41]
I have to have 20 characters but x is 22
7 0
3 years ago
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