The red part under the star is the solid base that the cylinder is standing in. It's probably wood or plastic, it's not free to move, and it's not involved in the experiment.

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2 years ago

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A 200kg ball on the end of string is swung in horizontal circle with radius of 0.5m . The ball makes revolution every 2second th

kondaur [170]

The speed of the ball is 1.57 m/s

Explanation:

We start by calculating the angular speed of the ball, which is given by

$\omega = \frac{2\pi}{T}$

where

T is the period of revolution

For the ball in this problem,

T = 2 s

(since the ball makes 1 revolution every 2 seconds)

So, the angular speed is

$\omega = \frac{2\pi}{T}=\frac{2\pi}{2}=\pi rad/s$

Now we can calculate the speed of the ball by using

$v=\omega r$

where

r = 0.5 m is the radius of the circular path

Substituting,

$v=(\pi)(0.5) = 1.57 m/s$

Learn more about angular motion:

brainly.com/question/9575487

brainly.com/question/9329700

brainly.com/question/2506028

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3 years ago