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sukhopar [10]
3 years ago
11

Friction is generated when?

Physics
1 answer:
valkas [14]3 years ago
8 0
Things are rubbed against each other
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A car starts from rest and reaches a velocity of 50.0 m/s in 41.0 seconds. What is the
Nataly_w [17]

Answer:

1.21 or 1.2 acceleration

Explanation:

i think it is 50.0/41.0

which would equal 1.21(depending on if you round it)

7 0
2 years ago
Read 2 more answers
A force of 5000 n is applied outwardly to each end of a 5.0-m long rod with a radius of 34.0 mm and a young's modulus of 125 x 1
Blizzard [7]
Por definicion tenemos que
 (F/A) = E(∆/0)
 Sustituyendo los valores tenemos y despejando ∆:
 ∆ = (F/(πr2 × E))*0
 (5000×5)/(3.14×(34×10^−2)^2×(125×10^8))
 5.5×10^−6 m
 
4 0
3 years ago
Read 2 more answers
Electric power is to be generated by installing a hydraulic turbine-generator at a site 115m below the free surface of a large r
Alina [70]

Answer:

W=1523kW

Explanation:

First, define the control volume for the energy balance. The most suitable control volume is that between the free surfaces of two reservoirs, the feeding reservoir, which is 115m above the turbine, and the final reservoir which is expected to be so close to the turbine because it will mean an energy waste if not.

With this control volume, write the energy balance:

Q+W=m*(\frac{P_{2}-P_{1}}{p}+g(z_{2}-z_{1})+\frac{v_{2}^{2}-v_{1}^{2}}{2}+H)

(Its formulation can be studied in Cengel (Fluid mechanics, chapter five).

Consider that both surfaces are at the same pressures (atmospheric pressure is expected for both), and both fluid velocities at the surfaces are close to zero because both reservoirs are so large and there is not considerable height change in the process. Q the heat flow (there is none), and H is the mechanic energy lost, which will be neglected because we are calculating the power generation potential, it means, its better possible power generation. Then the energy balance will be:

W=m*g(z_{2}-z_{1})

z_{2} is the height of the surface near the turbine, and z_{1} the height of the surface of the reservoir above. So, the power is:

W=1350*9.81*115=-1523002.5W

The sign is negative because the balance equation was formulated thinking that the energy is going out of the fluid, but it will be considered positive if we are considering the produced energy (the sign depends on what you are analyzing).

So, the power generation potential is:

W=1523kW

3 0
3 years ago
If a salmon swims straight upward in the water as fast enough to break through the surface at a speed of 5 meters per second, ho
Wewaii [24]

In this problem, the formula we can use is:

v^2 = v0^2 – 2gd

where,

v = final velocity = 0 at the peak

v0 = 5 m/s

g = gravitational acceleration = 9.81 m/s^2

d = distance travelled

 

Calculating for d:

0 = 5^2 – 2(9.81) d

<span>d = 1.27 m</span>

3 0
3 years ago
How much of a 100 g sample of radon-222 will remain unchanged after 7.64<br> days?
Lunna [17]

The half-life of a substance describes the time in which it takes for half of the radioactive isotope to decay into another form. In your question, it says that the half life of radon-222 is 3.82 days; in a 100g sample of radon, 3.82 days pass and 50g of that isotope is left.

7.64 days is the equivalent to two half lives (7.64/3.82), so only half of half of 100%, or 25%, of the isotope would remain. The answer is D

Hope that helps

6 0
3 years ago
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