Question

A wheel rotates with a constant angular acceleration of 3.45 rad/s^2. Assume the angular speed of the wheel is 1.85 rad/s at ti = 0.
(a) Through what angle does the wheel rotate between t = 0 and t = 2.00 s

Answer 1

Answer:

θ =607.33°

Explanation:

Given that

Angular acceleration α = 3.45 rad/s²

Initial angular speed ,ω = 1.85 rad/s

The angle rotates by wheel in time t

$\theta=\omega t +\dfrac{1}{2}\alpha t^2$

Now by putting the values

$\theta=\omega t +\dfrac{1}{2}\alpha t^2$

$\theta=1.85\times 2 +\dfrac{1}{2}\times 3.45\times 2^2$

θ = 10.6 rad

$\theta=\dfrac{180}{\pi}\times 10.6\ degree$

θ =607.33°

Therefore angle turn by wheel in 2 s is θ =607.33°