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Trava [24]
3 years ago
11

A cannonball is launched off a 100 m cliff horizontally with an initial velocity of 50 m/s. The goal is to have the cannonball t

ravel a target distance of 400m. Based on this, will the cannonball reach the target distance?
a)

Yes, the cannonball will hit its goal


b)

No, the cannonball will overshoot its goal


c)

No, the cannonball will fall short of the goal


d)

More information is needed to determine the outcome
Physics
1 answer:
Rudiy273 years ago
7 0

Answer: It will fall short of its goal.

Explanation: I took the quiz.

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All else equal, the payback period for a project will decrease whenever the_______.
telo118 [61]

Answer:

(B) cash inflows are moved earlier in time.

Explanation:

The payback period stated time-frame during which the initial amount of investment should be recovered. It is expressed in the year form

The formula to compute the payback period is shown below:

Payback period = Initial investment ÷ Net cash flow

where,  

The net cash flow = annual net operating income + depreciation expenses

The payback period of the project decreases when the accumulated starting year cash flows increases that results the movement of the cash inflows earlier in time

3 0
3 years ago
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Which one is having lesser ressistance. a 60w bulb or a 40w bulb?
Ivan
Power dissipation = (voltage across the component)² / (resistance of the component)

Since the resistance is in the denominator of the fraction in this formula for the
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So the <u>60w bulb</u> has lower resistance than the 40w bulb.
8 0
3 years ago
35) Kinetic energy in flowing water drives
Paha777 [63]

Answer:

C) Turbines

Explanation:

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8 0
3 years ago
Auroras are frequently seen
Kipish [7]
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3 0
3 years ago
A 300 gg ball on a 70-cmcm-long string is swung in a vertical circle about a point 200 cmcm above the floor. The string suddenly
Ratling [72]

Answer:

the   tension in the string an instant before it broke = 34 N

Explanation:

Given that :

mass of the ball m = 300 g = 0.300 kg

length of the string r = 70 cm = 0.7 m

At highest point, law of conservation of energy can be expressed as :

\frac{1}{2} mv^2 = mgh\\\\v = \sqrt{2gh}\\\\v = \sqrt{2*(9.8 \  m/s^2)*(6.00 \ m - 2.00 \ m)}\\\\

v = 8.854 \ m/s

The tension in the string is:

T = \frac{mv^2}{r}\\\\T = \frac{(0.300 \ kg)*(8.854 \ m/s^2)}{0.70 \ m}\\\\T = 33.59 N\\\\T = 34 \ N

Thus, the   tension in the string an instant before it broke = 34 N

6 0
3 years ago
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