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Trava [24]
3 years ago
11

A cannonball is launched off a 100 m cliff horizontally with an initial velocity of 50 m/s. The goal is to have the cannonball t

ravel a target distance of 400m. Based on this, will the cannonball reach the target distance?
a)

Yes, the cannonball will hit its goal


b)

No, the cannonball will overshoot its goal


c)

No, the cannonball will fall short of the goal


d)

More information is needed to determine the outcome
Physics
1 answer:
Rudiy273 years ago
7 0

Answer: It will fall short of its goal.

Explanation: I took the quiz.

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What is 1/12+7/9 hj​
Umnica [9.8K]

Explanation:

\frac{1}{12}  +  \frac{7}{9}  \\  \\  =  \frac{1 \times 3}{12 \times 3}  +  \frac{7 \times 4}{9 \times 4} \\  \\  =  \frac{3}{36}  +  \frac{28}{36}  \\  \\  =  \frac{3 + 28}{36}  \\  \\  =  \frac{31}{36}  \\  \\   \huge \purple{ \boxed{\therefore \:  \frac{1}{12}  +  \frac{7}{9}  =  \frac{31}{36} }} \\

6 0
2 years ago
Read 2 more answers
In the diagram, the wavelength is shown by :
MAXImum [283]

Answer:

i think the anwer is C

Explanation:

6 0
3 years ago
"Two long parallel wires 24.0 cm apart carry currents of 3.0 A and 8.0 A in the same direction. How far from the wire carrying 3
avanturin [10]

Answer:

6.5454 m

Explanation:

Let the distance from the wire carrying 3 A current is x

Then the distance from the the carrying current 8 A is 24-x

We know that magnetic field due to long wire is given by B=\frac{\mu _0i}{2\pi r}

It is given that magnetic field is zero at some distance so

\frac{\mu _0i_1}{2\pi x}=\frac{\mu _0i_2}{2\pi (24-x)}

Here i_1=3\ A \ and\  i_2=8\ A

So \frac{3}{x}=\frac{8}{24-x}=6.5454\ m

3 0
3 years ago
A parallel-plate capacitor with plates of area 600 cm^2 is charged to a potential difference V and is then disconnected from the
Julli [10]

Answer:

<h2>a) Q = 0.759µC</h2><h2>b) E = 39.5µJ</h2>

Explanation:

a) The charge Q on the positive charge capacitor can be gotten using the formula Q = CV

C = capacitance of the capacitor (in Farads )

V = voltage (in volts) = 100V

C = ∈A/d

∈ = permittivity of free space = 8.85 × 10^-12 F/m

A = cross sectional area = 600 cm²

d= distance between the plates = 0.7cm

C = 8.85 × 10^-12 * 600/0.7

C = 7.59*10^-9Farads

Q = 7.59*10^-9 * 100

Q = 7.59*10^-7Coulombs

Q = 0.759*10^-6C

Q = 0.759µC

b) Energy stored in a capacitor is expressed as E = 1/2CV²

E = 1/2 * 7.59*10^-9 * 100²

E = 0.0000395Joules

E = 39.5*10^-6Joules

E = 39.5µJ

7 0
2 years ago
A photon with a wavelength of 2.29 × 10^–7 meter strikes a mercury atom in the ground state.
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The photon can be absorbed and the energy of the photon is exactly equal to the energy-level difference between the ground state and the level d.

8 0
3 years ago
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