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lapo4ka [179]
3 years ago
5

Which of these ionic compounds have polyatomic ions? Check all that apply.

Physics
2 answers:
timama [110]3 years ago
7 0

Answer:

the answer is CaCO₃ and  NaOH.

Explanation:

Taya2010 [7]3 years ago
5 0

Answer:

  • CaCO₃ and
  • NaOH.

Explanation:

Polyatomic ions are ions that contain more than one atom in each one of the ions.  

Ionic compounds are made of cations (positive ions) and anions (negative ion). By convention, the cation is written before the anion.

List the ions in each compound:

<h3>CaCO₃</h3>

Cation: \rm Ca^{2+},

Anion: \rm {CO_3}^{2-}.

\rm Ca^{2+} is a monatomic ion for it contains only one atom in each ion.

\rm {CO_3}^{2-} is a polyatomic ion for it contains four atoms (one C atom and three O atoms) in each ion.

<h3>NaF</h3>

Cation: \rm Na^{+},

Anion: \rm F^{-}.

Both \rm Na^{+} and \rm F^{-} are monatomic for they contain only one atom in each ion.

<h3>FeO</h3>

Cation: \rm Fe^{2+},

Anion: \rm {O}^{2-}.

Both \rm Fe^{2+} and \rm O^{2-} are monatomic for they contain only one atom in each ion.

<h3>CaCl₂</h3>

Cation: \rm Ca^{2+},

Anion: \rm {Cl}^{-}.

Both \rm Ca^{2+} and \rm Cl^{-} are monatomic for they contain only one atom in each ion.

<h3>NaOH</h3>

Cation: \rm Na^{+},

Anion: \rm {OH}^{-}.

\rm Na^{+} is a monatomic ion for it contains only one atom in each ion.

\rm {OH}^{-} is a polyatomic ion for it contains two atoms (one O atom and one H atom) in each ion.

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Answer: a) 3.85 days

b) 10.54 days

Explanation:-

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = time taken for decomposition  = 3 days

a = let initial amount of the reactant  = 100 g

a - x = amount left after decay process  = \frac{58}{100}\times 100=58g

First we have to calculate the rate constant, we use the formula :

Now put all the given values in above equation, we get

k=\frac{2.303}{3}\log\frac{100}{58}

k=0.18days^{-1}

a) Half-life of radon-222:

t_{\frac{1}{2}}=\frac{0.693}{k}

t_{\frac{1}{2}}=\frac{0.693}{0.18}=3.85days

Thus half-life of radon-222 is 3.85 days.

b) Time taken for the sample to decay to 15% of its original amount:

where,

k = rate constant  = 0.18days^{-1}

t = time taken for decomposition  = ?

a = let initial amount of the reactant  = 100 g

a - x = amount left after decay process  = \frac{15}{100}\times 100=15g

t=\frac{2.303}{0.18}\log\frac{100}{15}

t=10.54days

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3 0
3 years ago
If the magnitude of the magnetic field is 6.50 mT at a distance of 12.8 cm from a long straight current carrying wire, what is t
Lunna [17]

Answer: magnitude of the magnetic field at a distance of 19.4 cm from the wire=4.29mT

Explanation:

According to  Biot-Savart law, A magnetic field generated by a current  carrying wire at a distance is represented as

B=μ₀I/ 2πr

B = magnetic field intensity 1000 mT =1T, 6.50mT = 6.50 X 10^-3T

 μ₀ =permeability of free space  4π × 10−7 H/m

I = current intensity

r = radius, 100cm = 1m, 12.8 cm= 12.8 x 10^-2m

6.50 X 10^-3 =  μ₀ x I/ 2 π X 12.8 X 10^-2

I =6.50  X 10 ^-3 X 2π  X  X 12.8 X 10^-2/  4π × 10−7 H/m

I= 4160 A

when the magnetic field is at 19.4 cm from the wire

B=μ₀I/ 2πr

= 4π × 10−7 H/m x4160/ 2π x 19.4 x 10^-2

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Vikki [24]

Answer:

1) Final Temperature of the gas in A will be GREATER than the temperature in B

2) Diagram of both processes on a single PV has been uploaded below

3) The Initial  pressures in containers A and B is 3039.87 J/liters

4) the final volume of container B is 923.36 cm³

Explanation:

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mass of piston = 10 kg

Area = 100cm³

Volume V = 800 cm³ = 0.8 L

ideal gas constant R = 8.3 J/K·mol

1)

Final Temperature of the gas in A will b GREATER than the temperature in B

2)

Diagram of both processes on a single PV has been uploaded below,

3)

Initial  pressures in containers A and B

PV = nRT

P = RT/V

we substitute

P = (8.3 × 293) /  0.8

P = 2431.9 / 0.8

P = 3039.87 J/liters

Therefore, The Initial  pressures in containers A and B is 3039.87 J/liters

4)

Given that;

power = 25 W

time t = 15s

the final volume of container B = ?

we know that;

work done = power × time

work done = 25 × 15 = 375

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375 = 3039.87 ( V₂ - 0.8 )

( V₂ - 0.8 ) = 375 / 3039.87

V₂ - 0.8 = 0.12336

V₂ = 0.12336 + 0.8

V₂ = 0.92336 Litres

V₂ = 923.36 cm³

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