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vladimir2022 [97]
3 years ago
15

Which inequality is represented by this graph? Also, if someone could tell me how this works that would be great :D

Mathematics
1 answer:
inysia [295]3 years ago
5 0

Answer:

y > -1/6 x+1

Step-by-step explanation:

The graph line is dotted.  Dotted lines means greater than or less than.  ( <, >)

Solid lines means less than or equal to     or greater than or equal to   (≤,≥)


Since the graph is shaded above the line, that means y is greater than the line.  If it were shaded below the line,  y would be less than.

y > -1/6 x+1

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A business with two locations buys seven large delivery trucks and five small delivery trucks. Location A receives three large t
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Answer:

cost of large delivery truck = $60,000

cost of small delivery truck = $45,000

Step-by-step explanation:

let,

the cost of large delivery truck = 'x'

the cost of small delivery truck = 'y'

Now, according to the question,

3x + 2y = 270000

4x + 3y = 375000

By solving the above 2 equation , we get;

x = 60000

y = 45000

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You are going to play a game where you bet a dollar and get to flip a coin ten (10) times. If you get four (4) heads in a row, y
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Approximately 4,000 times

Step-by-step explanation:

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Evaluate m – n if m = –16 and n = 28
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Step-by-step explanation:

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A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of
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Answer:

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

Step-by-step explanation:

Data given and notation

\bar X=250000 represent the sample mean  

s=37500 represent the standard deviation for the sample

n=5 sample size  

\mu_o =210250 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:  

Null hypothesis:\mu \leq 210250  

Alternative hypothesis:\mu > 210250  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

Conclusion

Since is a one right tailed test the p value would be:  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

6 0
3 years ago
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