Question

A sled and rider (combined mass of 69 kg) finish a downhill run with a speed of 30 m/s, then enter a flat (horizontal) area where the sled slows down at a constant rate of -2.3 m/(s^2) until it stops. What distance did the sled move while slowing down?

Answer 1

Answer:

Distance that sled move while slowing down= 195.65m

Explanation:

Distance traveled by sled after slowing down=S

acceleration at the start= -2.3 m/s2

initial speed u=30m/s

final speed=v

By using the equation

$v^{2} =u^{2} +2as$

Final speed is zero.

Therefore;

$0=30^{2} +2*(-2.3)*s\\2*2.3s=30^{2} \\s=30^{2} /(2*2.3)\\s=195.65 m$