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3 years ago

Which of the following is a reason why microbes were found to be problematic?

2 answers:

8 0

Microbes are found to be problematic for two reasons that they cause infection and sometime these organisms does not respond to antibiotics.

<u> Explanation: </u>

The microbes can cause infections in humans is a problem. Fungi, helminths and protozoans are the major cause of infectious diseases. Resistance to an antibiotic occurs when an ability to defeat drugs created to kill them are developed in a microbe. When a microbe becomes resistant, the antibiotics cannot fight against them and hence they multiply.

Antibiotic resistance is an urgent threat to the health of the public. They become a threat, when a microbe become resistant to antibiotic and it will be very difficult to destroy them. The resistance to antibiotics can cause serious issues like disability or even cause death.

-Dominant- [34]3 years ago

3 0

Answer:

I believe the answer is B.

Explanation:

Microbes could cause infectious diseases like for Ex: Flu and measles or heart diseases.

Hope my answer has helped you! :)

You might be interested in

1. A dog of mass 5 kg jumps on a table of mass 30 kg. As the dog walks around on the table, what is the average force that the t

Oksana_A [137]

Answer:

50N

The table is managing to keep the dog up, the dog is not moving up or down so the force that the table applies to the dog must be equal to the dogs weight - I draw this conclusion from Newton's 3rd law.

W= mg

W = 5 × 9.8

W = 49N

round to.one significant figure = 50N

5 0

3 years ago

In class we calculated the range of a projectile launched on flat ground. Consider instead, a projectile is launched down-slope

zysi [14]

Answer:

With an initial speed of 10m/s at an angle 30° below the horizontal, and a height of 8m, the projectile travels 7.49m horizontally before it lands.

Explanation:

Since the horizontal motion is independent from the vertical motion, we can consider them separated. The horizonal motion has a constant speed, because there is no external forces in the horizontal axis. On the other hand, the vertical motion actually is affected by the gravitational force, so the projectile will be accelerated down with a magnitude $g$ .

If we have the initial velocity $v_o$ and its angle $\theta$ , we can obtain the vertical component of the velocity $v_{oy}$ using trigonometry:

$v_{oy}=v_osin\theta$

Therefore, if we know the height at which the projectile was launched, we can obtain the final velocity using the formula:

$v_{fy}^{2} =v_{oy}^{2}+2gy\\\\ v_{fy}=\sqrt{v_{oy}^{2}+2gy }$

Next, we compute the time the projectile lasts to reach the ground using the definition of acceleration:

$g=\frac{v_{fy}-v_{oy}}{\Delta t} \\\\\Delta t= \frac{v_{fy}-v_{oy}}{g}=\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}$

Finally, from the equation of horizontal motion with constant speed, we have that:

$x=v_{ox}\Delta t= v_{ox}\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}$

For example, if the projectile is launched at an angle 30° below the horizontal with an initial speed of 10m/s and a height 8m, we compute:

$v_{ox}=10\frac{m}{s} cos30=8.66\frac{m}{s}\\v_{oy}=10\frac{m}{s} sin30=5\frac{m}{s}\\\\x=8.66\frac{m}{s} \frac{\sqrt{(5\frac{m}{s}) ^{2}+2(9.8\frac{m}{s^{2}})8m}-5\frac{m}{s} }{9.8\frac{m}{s^{2} } } =7.49m$

In words, the projectile travels 7.49m horizontally before it lands.

8 0

4 years ago

A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a sound with

Ymorist [56]

Answer:

the frequency of the beats is 8.7687 kHz

Explanation:

Given the data in the question;

The frequency for stationary source and moving observer is;

f' = f( 1 +( v_observer/v_sound))

we know that, speed of sound in dry air = 343 m/s

so we substitute

f' = 41.2 kHz( 1 + (33.0 m/s / 343 m/s) ) = 41.2kHz( 1 + 0.0962) = 41.2kHz(1.0962)

f' = 45.1634 kHz

Now the frequency for stationary observer and moving source with frequency f' will be

f" = f'( 1 / (1 - ( v_observer/v_sound)))

45.1634 kHz( 343 / 343 - 33)

we substitute

f" = 45.1634 kHz( 1 / (1 - (33.0 m/s / 343 m/s)))

f" = 45.1634 kHz( 1 / (1 - 0.0962))

f" = 45.1634 kHz( 1 / 0.9038 )

f" = 45.1634 kHz( 1.1064 )

f" = 49.9687 kHz

Now the beat frequency will be;

f_beat = f' - f

we substitute

f_beat = 49.9687 kHz - 41.2 kHz

f_beat = 8.7687 kHz

Therefore, the frequency of the beats is 8.7687 kHz

7 0

3 years ago

A kayak took 5 hours to finish its trip on a river.If it traveled at an average speed of 18mph (mile per hour),What was the dist

weqwewe [10]

23feet because she went 18mph

8 0

3 years ago

Heather and Matthew take 45 s to walk eastward along a straight road to a store 72 m away. What is their average velocity?

vladimir1956 [14]

Answer:

v = 1.6 m/s

Explanation:

Given that,

Distance, d = 72 m

Time taken, t = 45 s

We need to find their average velocity. Average velocity of an object is given by total distance divided by total time taken.

$v=\dfrac{d}{t}\\\\v=\dfrac{72\ m}{45\ s}\\\\v=1.6\ m/s$

So, their average velocity is 1.6 m/s.

5 0

4 years ago