The number is 66.
Solution:
Let the number be x.
To find the number x using given conditions.
Start with the last condition.
It is less than 7 times 8 + 23 = 7 × 8 + 23 = 79
So, the number is less than 79 which implies x < 79.
Using condition (4),
It is greater than 5 times 4 = 5 × 4 = 20
So, the number is greater than 79 which implies x > 20.
Combining condition (4) and (7), we get 20 < x < 79.
Using condition (3) and (5),
The number is a multiple of 11 and 6.
The number which is multiplied by both 11 and 6 is 66, 132, ...
But here x lies between 20 < x < 79.
So x = 66.
66 is not odd number and the sum of the digits is divisible by 2.
Therefore condition (1) and (2) also satisfied.
Hence the number is 66.
The answer: - 2.3 ≥ b ; which does not correspond with any of the answer choices; but most closely corresponds with: "Answer choice: [B]: b > -2.3 ."
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Explanation:
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Assuming we have:
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2.7 is greater than <u><em>or</em></u> equal to "(b + 5)";
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We would write:
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→ 2.7 ≥ b + 5 ;
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→ Subtract "5" from EACH side:
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→ 2.7 − 5 ≥ b + 5 − 5
→ - 2.3 ≥ b ; which does not correspond with any of the answer choices; but most closely corresponds with: "Answer choice: [B]: b > -2.3 ."
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You divide 2 by 9 which is .2222--- or .2 if you round it to the nearest tenths.
Whenever you want to change a fraction to a decimal, you divide the numerator by the denominator.
The answer would be D. 88:2
hope this hells!!
Answer:
<em>length</em><em> </em><em>l</em><em> </em><em>=</em><em>150</em><em> </em>
<em>breadth</em><em> </em><em>b</em><em> </em><em>=</em><em> </em><em>80</em><em> </em>
<em>lf</em><em> </em><em>2</em><em> </em><em>m</em><em> </em><em>wide</em><em> </em><em> </em><em>of</em><em> </em><em>road</em><em> </em><em>is</em><em> </em><em>inside</em><em> </em><em>the</em><em> </em><em>garden</em>
<em>then</em>
<em>lt's</em><em> </em><em>area</em><em> </em><em>=</em><em> </em><em>l</em><em> </em><em>×</em><em>b</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>150</em><em> </em><em>×</em><em> </em><em>2</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>300m</em><em>^</em><em>2</em>
