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nikklg [1K]
2 years ago
12

Please help soon! Thanks! Solve for x

Mathematics
1 answer:
spin [16.1K]2 years ago
5 0

Answer:

x=27\degree

Step-by-step explanation:

\because AC || DE.... (given)

\therefore m\angle CAD= m\angle EDF\\ (corresponding \: \angle s)

\therefore m\angle BAD= m\angle EDF\\(\because B\in \overleftrightarrow{AC})

\therefore m\angle BAD= 2x\\(\because m\angle EDF=2x)

In\:\triangle BAD,

m\angle BAD+m\angle BDA+m\angle ABD= 180\degree

2x+2x+72\degree = 180\degree

4x= 180\degree -72\degree

4x= 108\degree

x= \frac {108\degree}{4}

x=27\degree

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Follows are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attachment file.

n_1 = 26 \\\\ x_1 = 16.12 \\\\s_1 = 3.58\\\\n_2 = 26\\\\ x_2 = 19.85 \\\\ s_2 = 4.51

H_0: u_1 = u_2\\\\H_1: u_1 \neq u_2

Using formula:

\to S^{2}_{p}=\frac{S^{2}_{1}(n_1 -1)+ S^{2}_{2}(n_2-1)}{n_1+n_2-2}

\to Sp^2 = \frac{((26-1) \times (3.58^2) + (26-1) \times (4.51^2))}{(26+26-2)}

          = \frac{((25) \times 12.8164 + (25) \times 20.3401 )}{(26+24)}\\\\ = \frac{(320.41 + 508.5025)}{(50)}\\\\ = \frac{(828.9125)}{(50)}\\\\=16.57825

\to Sp = 4.0716

Calculating the value of standard error:

\to SE = Sp \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2}}

          =4.0716 \times \sqrt{\frac{1}{26}+\frac{1}{26}}\\\\=4.0716 \times \sqrt{\frac{1+1}{26}}\\\\=4.0716 \times \sqrt{\frac{2}{26}}\\\\=4.0716 \times \sqrt{\frac{1}{13}}\\\\=4.0716 \times 0.277 \\\\=1.1278332\\\\= 1.1293

Calculating the value of test statistic:

Formula:

\to t = \frac{(x_1-x_2)}{SE}

      = \frac{(16.12 -19.85)}{1.1293}\\\\= \frac{(-3.73)}{1.1293}\\\\=-3.303

Calculating the value of Degree of freedom:

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Yeah, certain data show clearly that the means are different.

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Answer:

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b)sample\hspace{0.1cm} mean 1 = \frac{65 + 69 + 77}{3} = 70.3

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Step-by-step explanation:

i) population size, N = 9

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