Answer:
0.665
Step-by-step explanation:
Given: 100 people are split into two groups 70 and 30. I group is given cough syrup treatment but second group did not.
Prob for a person to be in the cough medication group = 0.70
Out of people who received medication, 34% did not have cough
Prob for a person to be in cough medication and did not have cough
=
Prob for a person to be not in cough medication and did not have cough
=
Probability for a person not to have cough
= P(M1C')+P(M2C')
where M1 = event of having medication and M2 = not having medication and C' not having cough
This is because M1 and M2 are mutually exclusive and exhaustive
SO P(C') = 0.397+0.2=0.597
Hence required prob =P(M1/C') = 
It would be true no explanation needed
1-7
3-21
5-35
7-49
Hope this helps!
Answer:
66.6% or 0.66
Step-by-step explanation:
82% or 0.82 of All households have cable TV.
X = The number of households in a group of 6, that have cable TV.
You wish to find the proportion or percentage of groups for which EXACTLY 4 of 6 households will have cable TV.
82% of 6 is = 4.92
Approximately 4.92 out of 6 households, have cable TV.
Using this figure, you can now find out what % of 6 will give you 4.
Cross multiply:
0.82 - 4.92
M - 4
M = (4×0.82) ÷ 4.92 = 3.28÷4.92 = 0.666
Hence, 66.6% of 6 households, have cable TV. In other words, exactly 4 households (X=4) have cable TV.
To test, you can find what 66% of 6 is. You will get 4.
Answer:
Step-by-step explanation:
<u>Use the law of cosines:</u>
- cos C = (25² + 27² - 28²)/(2*25*27)
- cos C = 0.4222
- m∠C = arccos 0.4222
- m∠C = 65°
